Validate File Format

秒速五厘米 2022-08-10 17:50 163阅读 0赞

介绍

通过Schema来校验文件格式的正确与否。

package shuai.study.validator;
    
    import java.io.File;
    import java.io.IOException;
    import java.net.URL;
    
    import javax.xml.transform.Source;
    import javax.xml.transform.stream.StreamSource;
    import javax.xml.validation.Schema;
    import javax.xml.validation.SchemaFactory;
    import javax.xml.validation.Validator;
    
    import org.xml.sax.SAXException;
    
    public class FormatValidator {
    	public static boolean isFormatValid(URL urlSchema, Source source) {
    		boolean validatorFlag = true;
    
    		SchemaFactory schemaFactory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema");
    
    		try {
    			Schema schema = schemaFactory.newSchema(urlSchema);
    
    			Validator validator = schema.newValidator();
    			validator.validate(source);
    		} catch (SAXException se) {
    			validatorFlag = false;
    			se.printStackTrace();
    		} catch (IOException ioe) {
    			validatorFlag = false;
    			ioe.printStackTrace();
    		}
    
    		return validatorFlag;
    	}
    
    	public static void main(String[] args) {
    		URL urlSchema = FormatValidator.class.getResource("/schema/TestFileFormat.xsd");
    
    		String sourceFileString = FormatValidator.class.getResource("/xml/TestSourceFile.xml").getPath();
    		Source source = new StreamSource(new File(sourceFileString));
    
    		boolean validatorFlag = FormatValidator.isFormatValid(urlSchema, source);
    
    		if (validatorFlag) {
    			System.out.println("Analyze " + source.getSystemId() + " successfully");
    		} else {
    			System.out.println("Fail to analyze " + source.getSystemId());
    		}
    	}
    }