华为OJ试题：输入一行字符，分别统计出包含英文字母、空格、数字和其它字符的个数

女爷i 2022-08-09 00:50 214阅读 0赞

#include <stdarg.h>
    #include <stdio.h>
    #include <iostream>
    #include <vector>
    #include <string.h>
    #include <algorithm>
    #include <stdlib.h>
    #include <memory>
    #include <string.h>
    #include <set>
    #include <map>
    #include <sstream>
    #include <string>
    
    using namespace std;
    
    /* 求英文字母的大小*/
    static int getEnglishCharCount(string str)
    {
    	int len = str.size();
    	int i = 0;
    	int count = 0;
    
    	for (i = 0; i < len; i++)
    	{
    		if ((str[i] >= 'a' && str[i] <= 'z') || (str[i] >= 'A' && str[i] <= 'Z'))
    		{
    			++count;
    		}
    	}
    
    	return count;
    }
    
    /* 求空格字符的个数 */
    static int getBlankCharCount(string str)
    {
    	int len = str.size();
    	int i = 0;
    	int count = 0;
    
    	for (i = 0; i < len; i++)
    	{
    		if (str[i] == ' ')
    		{
    			++count;
    		}
    	}
    
    	return count;
    }
    
    /* 求数字字符的个数 */
    static int getNumberCharCount(string str)
    {
    	int len = str.size();
    	int i = 0;
    	int count = 0;
    
    	for (i = 0; i < len; i++)
    	{
    		if (str[i] >= '0' && str[i] <= '9')
    		{
    			++count;
    		}
    	}
    
    	return count;
    }
    
    /* 统计出其它字符的个数 */
    static int getOtherCharCount(string str)
    {
    	int count = str.size() - getEnglishCharCount(str);
    	count = count - getBlankCharCount(str);
    	count = count - getNumberCharCount(str);
    
    	return count;
    }
    
    int main()
    {
    
    	string str;
    
    	getline(cin, str);
    
    	cout << getEnglishCharCount(str) << endl;
    	cout << getBlankCharCount(str) << endl;
    	cout << getNumberCharCount(str) << endl;
    	cout << getOtherCharCount(str) << endl;
    
    	return 0;
    }