fastjson的部分使用

喜欢ヅ旅行 2022-08-04 09:22 102阅读 0赞

常用类型  
  
  
类型一：JavaBean  
  
  
类型二：List<JavaBean>  
  
  
类型三:List<String>  
  
  
类型四:List<Map<String,Object>>  
  
  
将上面的四种数据对象转换成json字符串的方法都是一样的  
  
  
String jsonString = JSON.toJSONString(obj);  
  
  
  
  
方法/步骤  
1  
将json字符串转化成JavaBean对象  
Person person = new Person("1","fastjson",1);  
//这里将javabean转化成json字符串  
String jsonString = JSON.toJSONString(person);  
//这里将json字符串转化成javabean对象,  
person =JSON.parseObject(jsonString,Person.class);  
2  
将json字符串转化成List<JavaBean>对象  
Person person1 = new Person("1","fastjson1",1);  
Person person2 = new Person("2","fastjson2",2);  
List<Person> persons = new ArrayList<Person>();  
persons.add(person1);  
persons.add(person2);  
String jsonString = JSON.toJSONString(persons);  
System.out.println("json字符串:"+jsonString);  
//解析json字符串  
List<Person> persons2 = JSON.parseArray(jsonString,Person.class);  
3  
将json字符串转化成List<String>对象  
List<String> list = new ArrayList<String>();  
list.add("fastjson1");  
list.add("fastjson2");  
list.add("fastjson3");  
String jsonString = JSON.toJSONString(list);  
System.out.println("json字符串:"+jsonString);  
//解析json字符串  
List<String> list2 = JSON.parseObject(jsonString,new TypeReference<List<String>>()\{\});   
4  
将json字符串转化成List<Map<String,Object>>对象  
Map<String,Object> map = new HashMap<String,Object>();  
map.put("key1", "value1");  
map.put("key2", "value2");  
Map<String,Object> map2 = new HashMap<String,Object>();  
map2.put("key1", 1);  
map2.put("key2", 2);  
List<Map<String,Object>> list = new ArrayList<Map<String,Object>>();  
list.add(map);  
list.add(map2);  
String jsonString = JSON.toJSONString(list);  
System.out.println("json字符串:"+jsonString);  
//解析json字符串  
List<Map<String,Object>> list2 = JSON.parseObject(jsonString,new TypeReference<List<Map<String,Object>>>()\{\});