编个“猜数字”玩玩

冷不防 2022-08-03 23:05 193阅读 0赞

一日午晌，顿觉百无聊赖，阵阵哈切之余，竟忆起儿时游玩之小游戏，名曰“猜数字”，此物规则甚是简单，游玩之时仅需猜测一四位数字，接着便可得到相应之正误结果，然后依此继续猜测，如此周而复始，直至猜测功成。

如诸位看官依然不甚了了亦无甚大碍，容我在此以一简单示例剖析之：

譬有一数字1234，游玩者之目的即将其猜出，游戏伊始，游玩之人自不知其所需猜测之数字为何，故其可能胡诌一数字，譬如4253，此猜测数字较之原数字而言，大抵有以下之特点，第一便是数字2，其出现于原数字之中，亦出现于猜测之数之中，并且其所在位置亦相同，皆在百位，故此数可谓之精准匹配，称其为A类型数字；与之相比，数字3虽亦出现于原数字及猜测数字之中，然其位置并不相同，一个处十位，一个处个位，此类数字可谓之次准匹配，称其为B类型数字，故猜测者报出4253之猜测时，其会得到1A1B之反馈，意为猜测数字之中共有一个A类型之数字、一个B类型之数字，猜测之人依此结果继续猜测，直至猜出，一般而言，猜测次数最少之人获胜，有时亦可纳入时间限制之考量。

现时思量一番，与其无聊，不如编写个“猜数字”以期自娱自乐，以免大好韶华匆匆而逝，老大来追悔莫及，既然如此，何不马上动手，图形界面？鼠标跟踪？此等花哨之事大可不必，黑白一个单调控制台，足矣足矣 **:)**

在此便列出全部之实现代码，数来也不过区区一百来行，如果看官有意，大可完整复制黏贴并编译之 **:)** ( 本人所用编译器为MinGW(gcc)，故并不保证在VC中亦可顺利通过，见谅见谅 )

\#include <iostream> using std::ostream; using std::endl; using std::cout; using std::cin; const int NUMBERS\_COUNT = 10;//0~9 const int NUMBERS\_GUESS = 4;//guess number consist of 4 number int g\_count\[NUMBERS\_COUNT\];//store the counts of numbers (0~9) int g\_buffer\[NUMBERS\_COUNT\]\[NUMBERS\_GUESS\];//store the value and number //init g\_count and g\_buffer array void Init() \{ for( int i = 0; i < NUMBERS\_COUNT; ++i ) \{ g\_count\[i\] = 0; for( int j = 0; j < NUMBERS\_GUESS; ++j ) \{ g\_buffer\[i\]\[j\] = 0; \} \} \} struct GuessResult \{ int ACount;//the position and value are both right int BCount;//just the value is right GuessResult():ACount(0),BCount(0) \{\}; friend ostream& operator << ( ostream& o, const GuessResult& gr ); \}; ostream& operator << ( ostream& o, const GuessResult& gr ) \{ cout<<gr.ACount<<" A "<<gr.BCount<<" B "; \} GuessResult Evaluate( char originNumber\[NUMBERS\_GUESS+1\], char guessNumber\[NUMBERS\_GUESS+1\] ) \{ Init(); //get the information of the originNumber for( int i = 0; i < NUMBERS\_GUESS; ++i ) \{ ++g\_count\[ originNumber\[i\]-'0' \]; g\_buffer\[originNumber\[i\]-'0'\]\[i\] = 1; \} GuessResult gr; for( int i = 0; i < NUMBERS\_GUESS; ++i ) \{ if( g\_buffer\[ guessNumber\[i\]-'0' \]\[i\] == 1 )//position and value are both match \{ ++gr.ACount; --g\_count\[ guessNumber\[i\]-'0' \];//reduce the count of the number \} \} for( int i = 0; i < NUMBERS\_GUESS; ++i ) \{ if( g\_buffer\[ guessNumber\[i\]-'0' \]\[i\] != 1 && g\_count\[ guessNumber\[i\]-'0' \] > 0 )//just value match \{ ++gr.BCount; --g\_count\[ guessNumber\[i\]-'0' \]; \} \} return gr; \} void GenGuessNumber( char number\[NUMBERS\_GUESS+1\] ) \{ srand( time(NULL) ); for( int i = 0; i < NUMBERS\_GUESS; ++i ) \{ int num = rand() % NUMBERS\_COUNT; number\[i\] = num + '0'; \} number\[NUMBERS\_GUESS\] = '/0'; \} int main() \{ char originNumber\[NUMBERS\_GUESS+1\]; char guessNumber\[NUMBERS\_GUESS+1\]; GenGuessNumber( originNumber ); bool isGuessRight = false; int guessCount = 0; while( !isGuessRight ) \{ cout<<"Please input the number you've guessed : "<<endl; cin >> guessNumber; if( Evaluate( originNumber, guessNumber ).ACount == NUMBERS\_GUESS ) \{ cout<<"You Are Greate!!!"<<endl; cout<<"You've Guessed "<<guessCount<<" Times ."<<endl; isGuessRight = true; \} else \{ cout<<"The Result Is : "<<endl <<Evaluate( originNumber, guessNumber )<<endl; ++guessCount; \} \} system( "pause" ); return 0; \}