leetcode 134. Gas Station

╰半夏微凉° 2022-07-30 13:57 136阅读 0赞

There are N gas stations along a circular route, where the amount of gas at station i is `gas[i]`.

You have a car with an unlimited gas tank and it costs `cost[i]` of gas to travel from station i to its next station (i\+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.

Note:  
The solution is guaranteed to be unique.

很明显，起点要从gas-cost大于零的地方开始，如果有连续的这样的点，只选取第一个这样的点。

class Solution {
    public:
    	int canCompleteCircuit(vector<int>& gas, vector<int>& cost) {
    		if (gas.size() == 1)
    		{
    			if (gas[0] >= cost[0])
    				return 0;
    			else
    				return -1;
    		}
    		vector<int>starter;
    		int k = 0;
    		while (k < gas.size())
    		{
    			if (gas[k] - cost[k] > 0)
    			{
    				int kk = k;
    				starter.push_back(k);
    				while (kk < gas.size() && gas[kk] - cost[kk] >= 0)
    					kk++;
    				k = kk;
    			}
    			k++;
    		}
    		for (int i = 0; i < starter.size(); i++)
    		{
    			int rem = 0;
    			while (rem >= 0)
    			{
    				rem = gas[starter[i]] - cost[starter[i]];
    				int kk = starter[i];
    				int cnt = 1;
    				while (rem >= 0)
    				{
    					kk++;
    					if (kk == gas.size())
    						kk = 0;
    					rem += gas[kk] - cost[kk];
    					cnt++;
    					if (cnt == gas.size() && rem >= 0)
    						return starter[i];
    				}
    			}
    		}
    		return -1;
    	}
    };

accept

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