Java 单链表的反转以及双向链表的实现

￡神魔★判官ぃ 2022-07-28 00:28 122阅读 0赞

看代码吧， 详情都写在注释里了

单链表的反转：

/**
     *  单链表的反转 1<-2<-3<-4 ==> 1->2->3->4
     * 
     * @author he
     *
     */
    class Node<T> {
    	T item;
    	Node next = null;
    
    	public Node(T item) {
    		this.item = item;
    	}
    }
    
    public class reverseLinkedlist {
    
    	// 迭代实现链表反转
    	public static Node reverse(Node x) {
    		Node first = x;
    		Node reverse = null;
    		while (first != null) {
    			Node second = first.next;
    			first.next = reverse;
    			reverse = first;
    			first = second;
    		}
    
    		return reverse;
    	}
    
    	// 递归实现链表反转
    	public static Node reverseGcd(Node first) {
    		if (first == null) {
    			return null;
    		}
    		if (first.next == null) {
    			return first;
    		}
    		Node second = first.next;
    		second.next = first;
    		first.next = null;
    		Node rest = reverseGcd(second);
    		return rest;
    
    	}
    
    	public static void main(String[] args) {
    		Node<Integer> node = new Node<Integer>(1);
    		node.next = new Node<Integer>(2);
    		node.next.next = new Node<Integer>(3);
    		System.out.println(reverse(node).item);// 3
    		System.out.println(reverseGcd(node).item);// 1 ,true 因为链表已经被反转过一次
    
    	}
    
    }

双向链表的实现：

/**
     * P104 T31 双向链表 相当于简化版的Linkedlist
     * 主要实现了从表头，表尾插入一个结点，在指定结点之前或之后插入一个结点，
     * 从表头，表尾删除一个结点，删除指定结点 
     * 指定索引返回结点
     * 
     * 
     * 测试通过；
     * 
     * @author he
     *
     */
    class DoubleNode<T> {
    	private int N;// 记录元素个数
    	private Node first;// 头结点
    	private Node last;// 尾结点
    
    	private class Node {
    		T item;
    		Node perv;// 前一个结点
    		Node next;// 后一个结点
    
    		@Override
    		public String toString() {
    			// TODO Auto-generated method stub
    			return item + "";
    		}
    	}
    
    	// 根据索引获取结点
    	public Node getNode(int index) {
    		if (index < 0 || index >= N) {
    			throw new IndexOutOfBoundsException();
    		}
    
    		Node node = first;
    
    		for (int i = 0; i < index; i++) {
    			node = node.next;
    		}
    
    		return node;
    	}
    
    	// 判断是否为空
    	public boolean isEmpty() {
    		return N == 0;
    	}
    
    	// 元素个数
    	public int size() {
    		return N;
    	}
    
    	// 表头插入结点
    	public void pushFirst(T item) {
    
    		Node oldfirst = first;
    		first = new Node();
    		first.item = item;
    		if (isEmpty()) {
    			last = first;
    		} else {
    			first.next = oldfirst;
    			oldfirst.perv = first;
    		}
    		N++;
    	}
    
    	// 在指定结点前添加新结点
    	public void pushBefore(Node newnode, Node node) {
    		newnode.next = node;
    		newnode.perv = node.perv;
    		newnode.next.perv = newnode;
    		// 防止在头结点前面插入新结点
    		if (newnode.perv != null) {
    			newnode.perv.next = newnode;
    		}
    		N++;
    	}
    
    	// 在指定索引前插入新结点
    	public void pushBeforeOfIndex(T item, int index) {
    		Node node = getNode(index);
    		Node newnode = new Node();
    		newnode.item = item;
    		pushBefore(newnode, node);
    	}
    
    	// 从表尾插入
    	public void pushLast(T item) {
    		Node oldlast = last;
    		last = new Node();
    		last.item = item;
    		last.next = null;
    		if (isEmpty()) {
    			first = last;
    		} else {
    			oldlast.next = last;
    			last.perv = oldlast;
    		}
    		N++;
    	}
    
    	// 在指定结点后添加新结点
    	public void pushAfter(Node newnode, Node node) {
    		newnode.perv = node;
    		newnode.next = node.next;
    		newnode.perv.next = newnode;
    		// 防止在尾结点之后插入新结点
    		if (newnode.next != null) {
    			newnode.next.perv = newnode;
    		}
    		N++;
    	}
    
    	// 在指定索引之后添加结点
    	public void pushAfterOfIndex(T item, int index) {
    		Node newnode = new Node();
    		newnode.item = item;
    		Node node = getNode(index);
    		pushAfter(newnode, node);
    
    	}
    
    	// 从表头删除一个结点
    	public void popFirst() {
    		first = first.next;
    		if (first != null) {
    			first.perv = null;
    		}
    		N--;
    	}
    
    	// 从表为删除一个结点
    	public void popLast() {
    		last.perv.next = null;
    		last.perv = null;
    		N--;
    	}
    
    	// 删除指定的结点
    	public void pop(Node node) {
    
    		node.perv.next = node.next;
    		node.next.perv = node.perv;
    		node.perv = null;
    		node.next = null;
    		N--;
    	}
    
    	// 删除指定索引的结点
    	public void popOfIndex(int index) {
    		if (index == 0) {
    			popFirst();
    		} else if (index == N - 1) {
    			popLast();
    		} else {
    			Node node = getNode(index);
    			pop(node);
    		}
    
    	}
    
    	@Override
    	public String toString() {
    		StringBuilder sb = new StringBuilder();
    		Node node = first;
    		for (int i = 0; i < N; i++) {
    			sb.append("[");
    			sb.append(node);
    			sb.append("]");
    			sb.append(",");
    			node = node.next;
    		}
    		return sb.toString();
    	}
    
    }
    
    public class DoubleLinkedlist {
    	public static void main(String[] args) {
    		DoubleNode<Integer> d = new DoubleNode<Integer>();
    		d.pushFirst(1);
    		d.pushFirst(2);
    		d.pushFirst(3);
    		// d.pushFirst(4);
    		d.pushLast(5);
    		// d.pushLast(6);
    		// System.out.println(d.size());
    		// d.pushBeforeOfIndex(10, 1);
    		// d.pushAfterOfIndex(9, 0);
    		// d.popFirst();
    		// d.popFirst();
    		d.popOfIndex(0);
    		// d.popOfIndex(3);
    		// d.popLast();
    		System.out.println(d.toString());
    		// System.out.println(d.getNode(2));
    	}
    
    }