4-2 电子时钟中的运算符重载

Love The Way You Lie 2022-07-15 15:12 170阅读 0赞

[4-2 电子时钟中的运算符重载][4-2]

#include<iostream>
    #include<cstring>
    using namespace std;
    int a,b,c;
    class Time
    {
    public :
        Time (){
       hour=0;minute=0;sec=0;}
        Time(int a,int b,int c):hour(a),minute(b),sec(c){}
        Time operator ++();
        friend void putin(Time &t);
       friend  bool operator==( Time &a, Time &b) ;
       friend int getsum(Time &a) ;
       friend  bool operator >( Time &a, Time &b) ;
       void display();
    private:
        int hour;
        int minute;
        int sec;
    };
     bool operator==( Time &a, Time &b)
        {
            if(a.hour==b.hour&&a.minute==b.minute&&a.sec==b.sec)return 1;
            return 0;
        }
        int getsum(Time &a)
        {
            return a.hour*3600+a.minute*60+a.sec;
        }
        bool operator >( Time &a, Time &b)
        {
            if(getsum(a)>getsum(b))return 1;
            return 0;
        }
    void putin(Time &t)
    {
        cin>>t.hour>>t.minute>>t.sec;
        if(t.hour<0||t.hour>12)t.hour=12;
         if(t.sec<0||t.sec>59)t.sec=0;
          if(t.minute<0||t.minute>59)t.minute=0;
    }
    Time Time::operator++()
    {
        if(++sec>=60)
        {
            sec-=60;
    
    
        if(++minute>=60)
        {
            minute-=60;
            ++hour;
        }
        }
        return *this;
    }
    void Time::display()
    {
        if(hour<10)
            cout<<"0"<<hour<<":";
         else
            cout<<hour<<":";
        if(minute<10)
            cout<<"0"<<minute<<":";
        else
            cout<<minute<<":";
        if(sec<10)
            cout<<"0"<<sec;
        else
            cout<<sec;
        cout<<endl;
    }
    int main()
    {
        Time t1,t2;
        putin(t1);
        putin(t2);
        if(t1>t2)
          cout<<"The begin time is not earlier than the end time!"<<endl;
           else
        {
            while(!(t1>t2))
            {
                t1.display();
                ++t1;
            }
        }
        return 0;
    }

[4-2]: http://acm.sdut.edu.cn/onlinejudge2/index.php/Home/Contest/contestproblem/cid/1819/pid/2711.html