205. Isomorphic Strings (同构字符串判断)
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
Note:
You may assume both s and t have the same length.
import java.util.Hashtable;
public class Solution {
char index = 'a';
public boolean isIsomorphic(String s, String t) {
Map<Character,Character> table = new Hashtable<Character, Character>();
StringBuilder sb = new StringBuilder();
for(char ch:s.toCharArray()){
if(table.get(ch)==null){
table.put(ch, index++);
}
sb.append(table.get(ch));
}System.out.println(sb.toString());
table.clear();
index='a';
int pos=0;
for(char ch:t.toCharArray()){
if(table.get(ch)==null){
table.put(ch, index++);
}
if(table.get(ch)!=sb.charAt(pos++)){
return false;}
}return true;
}
}
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