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这是一道简单的中级题,本想上道题做完就不做了的,结果看到这个好简单就还是做一下吧~ [\141 Linked List Cycle][141 Linked List Cycl
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/\ 判断输入的链表是否是循环链表 思路:利用快慢指针,一个是p = p->next;另外一个是q = q->next;如果两个指针相遇了,则说明是循环链表 \/
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> 文章最前: 我是Octopus,这个名字来源于我的中文名--章鱼;我热爱编程、热爱算法、热爱开源。所有源码在我的个人[github][] ;这博客是记录我学习的点点滴滴,如
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