Servlets与JSP初学（书籍：head first系列）

一时失言乱红尘 2022-07-14 12:11 122阅读 0赞

按照书本上P30页的示例，尝试着编写部署运行一个简单Servlet

1.建立目录树

2.编写Ch1Servlet.java的Servlet

import javax.servlet.\*;  
import javax.servlet.http.\*;  
import java.io.\*;  
public class Ch1servlet extends HttpServlet\{  
public void doGet(HttpServletRequest reque,HttpServletResponse response)throws I0Exception\{  
PrintWriter out=response.getWriter();  
java.util.Data today=new java.util.Date();  
out.println("<html>"+"<body>"+"<h1 align=center>HF\\'s Chapter1 Servlet</h1>"+"<br>"+today+"</body>"+"</html>");  
\}  
\}

3.创建部署文件web.xml

<?xml version="1.0" encoding="ISO-8851-1"?>  
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"  
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee  
http://java.sun.com/xml/ns/j2ee/web-app\_2\_4.xsd"  
version="2.4">  
<servlet>  
<servlet-name>Chaper1 Servlet</servlet-name>  
<servlet-class>Ch1Servlet</servlet-class>  
</servlet>  
<servlet-mapping>  
<servlet-name>Chapter1 Servlet</servlet-name>  
<url-pattern>/serv1</url-pattern>  
</servlet-mapping>  
</web-app>

5编译servlet

%javac -classpath  /your path/tomcat/common/lib/Servlet-api.jar-d classes src/Ch1Servlet.java

进行到第五步时遇到了问题，对%javac -classpath感到疑惑

![Image 1][]

书上的例子乍一看非常简单，，万万没想到自己照着敲都遇到好多麻烦 .

[javac -classpath的使用][javac -classpath]

参考了相关的技术博客：http://www.blogjava.net/caizh2009/archive/2010/10/19/335634.html

还在理解中，希望明天能解决问题，先搭载出简单的Servlet，好好了解一下什么是Servlet

[Image 1]: 
[javac -classpath]: http://www.blogjava.net/caizh2009/archive/2010/10/19/335634.html