各系地图坐标互相转换【JS版和Java版】

野性酷女 2022-06-18 10:53 168阅读 0赞

# 各系地图坐标互相转换【JS版和Java版】 #

## 坐标说明 ##

1.（地球坐标）美国GPS使用的是WGS84的坐标系统，以经纬度的形式来表示地球平面上的某一个位置。  
2.（火星坐标）我国，出于国家安全考虑，国内所有导航电子地图必须使用国家测绘局制定的加密坐标系统，即将一个真实的经纬度坐标加密成一个不正确的经纬度坐标。

## 坐标关系 ##

百度地图API【百度坐标】  
腾讯搜搜地图API【火星坐标】  
搜狐搜狗地图API【搜狗坐标】  
阿里云地图API【火星坐标】  
图吧MapBar地图API【图吧坐标】  
高德MapABC地图API【火星坐标】  
灵图51ditu地图API【火星坐标】

## JS版 ##

### 百度转高德 ###

function bd_encrypt(gg_lon, gg_lat){ 
        var pi_value=Math.PI;
        var X_PI = pi_value * 3000.0 / 180.0;
        var x = gg_lon, y = gg_lat;
        var z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * X_PI);
        var theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * X_PI);
        var bd_lon = z * Math.cos(theta) + 0.0065;
        var bd_lat = z * Math.sin(theta) + 0.006;
        return {
            bd_lat: bd_lat,
            bd_lon: bd_lon
        };
    }

### 高德转百度 ###

function bd_decrypt(bd_lon,bd_lat) { 
        var pi_value=Math.PI;
        var X_PI = pi_value * 3000.0 / 180.0;
        var x = bd_lon - 0.0065;
        var y = bd_lat - 0.006;
        var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * X_PI);
        var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * X_PI);
        var gg_lon = z * Math.cos(theta);
        var gg_lat = z * Math.sin(theta);
        return {
            gg_lon: gg_lon,
            gg_lat: gg_lat
        }
    }

## Java版 ##

public class GPSUtil {   
        public static double pi = 3.1415926535897932384626;  
        public static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;  
        public static double a = 6378245.0;  
        public static double ee = 0.00669342162296594323;  
    
        public static double transformLat(double x, double y) {  
            double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y  
                    + 0.2 * Math.sqrt(Math.abs(x));  
            ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;  
            ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;  
            ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;  
            return ret;  
        }  
    
        public static double transformLon(double x, double y) {  
            double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1  
                    * Math.sqrt(Math.abs(x));  
            ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;  
            ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;  
            ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0  
                    * pi)) * 2.0 / 3.0;  
            return ret;  
        }  
        public static double[] transform(double lat, double lon) {  
            if (outOfChina(lat, lon)) {  
                return new double[]{lat,lon};  
            }  
            double dLat = transformLat(lon - 105.0, lat - 35.0);  
            double dLon = transformLon(lon - 105.0, lat - 35.0);  
            double radLat = lat / 180.0 * pi;  
            double magic = Math.sin(radLat);  
            magic = 1 - ee * magic * magic;  
            double sqrtMagic = Math.sqrt(magic);  
            dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);  
            dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);  
            double mgLat = lat + dLat;  
            double mgLon = lon + dLon;  
            return new double[]{mgLat,mgLon};  
        }  
        public static boolean outOfChina(double lat, double lon) {  
            if (lon < 72.004 || lon > 137.8347)  
                return true;  
            if (lat < 0.8293 || lat > 55.8271)  
                return true;  
            return false;  
        }  
        /** * 84 to 火星坐标系 (GCJ-02) World Geodetic System ==> Mars Geodetic System * * @param lat * @param lon * @return */  
        public static double[] gps84_To_Gcj02(double lat, double lon) {  
            if (outOfChina(lat, lon)) {  
                return new double[]{lat,lon};  
            }  
            double dLat = transformLat(lon - 105.0, lat - 35.0);  
            double dLon = transformLon(lon - 105.0, lat - 35.0);  
            double radLat = lat / 180.0 * pi;  
            double magic = Math.sin(radLat);  
            magic = 1 - ee * magic * magic;  
            double sqrtMagic = Math.sqrt(magic);  
            dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);  
            dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);  
            double mgLat = lat + dLat;  
            double mgLon = lon + dLon;  
            return new double[]{mgLat, mgLon};  
        }  
    
        /** * * 火星坐标系 (GCJ-02) to 84 * * @param lon * @param lat * @return * */  
        public static double[] gcj02_To_Gps84(double lat, double lon) {  
            double[] gps = transform(lat, lon);  
            double lontitude = lon * 2 - gps[1];  
            double latitude = lat * 2 - gps[0];  
            return new double[]{latitude, lontitude};  
        }  
        /** * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标 * * @param lat * @param lon */  
        public static double[] gcj02_To_Bd09(double lat, double lon) {  
            double x = lon, y = lat;  
            double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);  
            double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);  
            double tempLon = z * Math.cos(theta) + 0.0065;  
            double tempLat = z * Math.sin(theta) + 0.006;  
            double[] gps = {tempLat,tempLon};  
            return gps;  
        }  
    
        /** * * 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 * * 将 BD-09 坐标转换成GCJ-02 坐标 * * @param * bd_lat * @param bd_lon * @return */  
        public static double[] bd09_To_Gcj02(double lat, double lon) {  
            double x = lon - 0.0065, y = lat - 0.006;  
            double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);  
            double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);  
            double tempLon = z * Math.cos(theta);  
            double tempLat = z * Math.sin(theta);  
            double[] gps = {tempLat,tempLon};  
            return gps;  
        }  
    
        /**将gps84转为bd09 * @param lat * @param lon * @return */  
        public static double[] gps84_To_bd09(double lat,double lon){  
            double[] gcj02 = gps84_To_Gcj02(lat,lon);  
            double[] bd09 = gcj02_To_Bd09(gcj02[0],gcj02[1]);  
            return bd09;  
        }  
        public static double[] bd09_To_gps84(double lat,double lon){  
            double[] gcj02 = bd09_To_Gcj02(lat, lon);  
            double[] gps84 = gcj02_To_Gps84(gcj02[0], gcj02[1]);  
            //保留小数点后六位 
            gps84[0] = retain6(gps84[0]);  
            gps84[1] = retain6(gps84[1]);  
            return gps84;  
        }  
    
        /**保留小数点后六位 * @param num * @return */  
        private static double retain6(double num){  
            String result = String .format("%.6f", num);  
            return Double.valueOf(result);  
        }  
    
    }

## 问题 ##

1.  【JS版】如果js计算结果是NAN，则说明数字计算出问题了。

## 原文 ##

JS版本：[http://www.68idc.cn/help/makewebs/javascript/20151006571672.html][http_www.68idc.cn_help_makewebs_javascript_20151006571672.html]  
JAVA版本：[http://www.jianshu.com/p/d3dd4149bb0b][http_www.jianshu.com_p_d3dd4149bb0b]

[http_www.68idc.cn_help_makewebs_javascript_20151006571672.html]: http://www.68idc.cn/help/makewebs/javascript/20151006571672.html
[http_www.jianshu.com_p_d3dd4149bb0b]: http://www.jianshu.com/p/d3dd4149bb0b