Java对【JSON数据的解析】--fastjson解析法

我会带着你远行 2022-06-16 04:21 212阅读 0赞

**要求：解析下面JSON数据**

**String string = “\{no:1,name:’Android’,employees:\[\{name:’zhangsan’,age:20\},\{name:’lisi’,age:21\},\{name:’wangwu’,age:22\}\]\}”;**

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代码：

package com.qf.demo4;
    
    import java.util.ArrayList;
    
    import com.alibaba.fastjson.JSON;
    
    public class Test {
        
    
        public static void main(String[] args) {
            //fastjson解析数据
            //1.阿里解析过程和Gson类似，
            String string= "{no:1,name:'android',employees:[{name:'zhangsan',age:20},{name:'lisi',age:21},{name:'wangwu',age:22}]}";
    
            Employ employ = JSON.parseObject(string,Employ.class);
            System.out.println(employ);
        }
    }
    
    class Person{
        private String name;
        private int age;
        public Person(String name, int age) {
            super();
            this.name = name;
            this.age = age;
        }
        public Person() {
            super();
        }
        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public int getAge() {
            return age;
        }
        public void setAge(int age) {
            this.age = age;
        }
        @Override
        public String toString() {
            return "Person [name=" + name + ", age=" + age + "]";
        }
    
    
    }
    
    
    class Employ{
        private int no;
        private String name;
        private ArrayList<Person> employees;
        public Employ(int no, String name, ArrayList<Person> employees) {
            super();
            this.no = no;
            this.name = name;
            this.employees = employees;
        }
        public Employ() {
            super();
        }
        public int getNo() {
            return no;
        }
        public void setNo(int no) {
            this.no = no;
        }
        public String getName() {
            return name;
        }
        public void setName(String name) {
            this.name = name;
        }
        public ArrayList<Person> getEmployees() {
            return employees;
        }
        public void setEmployees(ArrayList<Person> employees) {
            this.employees = employees;
        }
        @Override
        public String toString() {
            return "Employ [no=" + no + ", name=" + name + ", employees=" + employees + "]";
        }
    
    }