org.springframework.web.servlet.DispatcherServlet noHandlerFound

r囧r小猫 2022-06-15 11:38 108阅读 0赞

### 页面显示      ![这里写图片描述][SouthEast]       ###

### 后台显示      org.springframework.web.servlet.DispatcherServlet noHandlerFound ###

No mapping found for HTTP request with URI [/springmvc_first/jsp/items/queryItem.action] in DispatcherServlet with name 'springmvc'

#### 访问的地址是：[`http://127.0.0.1/springmvc_first/jsp/items/queryItem.action`][http_127.0.0.1_springmvc_first_jsp_items_queryItem.action]      项目结构      ![这里写图片描述][SouthEast 1] ####

# 前端控制器的配置 #

<?xml version="1.0" encoding="UTF-8"?>
    <web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
        
      <servlet>
        <servlet-name>springmvc</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>classpath:springmvc.xml</param-value>
        </init-param>
      </servlet>
    
      <servlet-mapping>
        <servlet-name>springmvc</servlet-name>
        <url-pattern>*.action</url-pattern>
      </servlet-mapping>
    
    </web-app>

# 有人说是`*.action`的问题 #

再看一下在spring.xml中配置的Handler

<bean name="/queryItem.action" class="com.ld.springmvc.controller.ItemsController" />

#### 原来是访问路径的问题，配置的是/queryItem.action    ####

#### 访问的路径应该是：127.0.0.1/springmvc\_first/queryItem.action ####

[SouthEast]: /images/20220615/98711a2717d94b3b853ed4a7cb1d9723.png
[http_127.0.0.1_springmvc_first_jsp_items_queryItem.action]: http://127.0.0.1/springmvc_first/jsp/items/queryItem.action
[SouthEast 1]: /images/20220615/b56fa7be109a4878b0ed89163a08c878.png