struts1.x完整实例

妖狐艹你老母 2022-06-12 20:07 188阅读 0赞

1、简介

struts是WEB程序MVC分层架构中的C，属于控制层，主要进行处理用户的请求，基于请求驱动。获取用户的请求地址并将表单中的数据封装到Form对象后交给Action进行处理。在Action中进行条用业务层处理具体的请求后将结果通过ActionMapping封装跳转地址返回给用户。struts是对servlet的再次封装，使得更加灵活高效。下面以一个登录的实例讲解struts的开发过程。

2、在新建的web工程中添加以下struts1.x  jar包

antlr-2.7.6.jar、commons-beanutils.jar、commons-digester.jar、commons-fileupload.jar、commons-logging-1.0.4.jar、commons-validator.jar、jakarta-oro.jar、struts.jar。

3、web.xml进行如下配置

<?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
      <display-name>MyStruts1Prj</display-name>
      
      <servlet>
      	<servlet-name>action</servlet-name>
      	<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
      	
    	<init-param>
    		<param-name>config</param-name>
    		<param-value>/WEB-INF/conf/struts-config.xml</param-value>
    	</init-param>
    	<init-param>
    		<param-name>debug</param-name>
    		<param-value>3</param-value>
    	</init-param>
    	<init-param>
    		<param-name>detail</param-name>
    		<param-value>3</param-value>
    	</init-param>
    	
    	<load-on-startup>0</load-on-startup>
      </servlet>
      
      <servlet-mapping>
      	<servlet-name>action</servlet-name>
      	<url-pattern>*.do</url-pattern>
      </servlet-mapping>
      
      <welcome-file-list>
        <welcome-file>index.jsp</welcome-file>
      </welcome-file-list>
    </web-app>

4、新建登陆页面login.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <%
    	String basePath = request.getContextPath();
    %>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>登陆页面</title>
    </head>
    <body>
    	<h1>登陆页面</h1>
    	<hr>
    	<form action="<%=basePath %>/login.do" method="post" >
    		userName:<input id="userName" name="userName" type="text" /><br>
    		passWord:<input id="passWord" name="passWord" type="password" /><br>
    		<input type="submit" id="submit" name="submit" value="submit" />
    	</form>
    </body>
    </html>

5、新建登陆成功后的跳转页面loginSucces.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>登陆成功页面</title>
    </head>
    <body>
    	<h1>欢迎[<%=request.getAttribute("userName") %>]登陆成功！</h1>
    </body>
    </html>

6、新建登陆失败后的跳转页面loginError.jsp

<%@ page language="java" contentType="text/html; charset=UTF-8"
        pageEncoding="UTF-8"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>登陆失败页面</title>
    </head>
    <body>
    	<h1>登陆失败！</h1>
    </body>
    </html>

7、新建LoginActionForm.java

package com.lanp.webapp.form;
    
    import org.apache.struts.action.ActionForm;
    
    /**
     * 封装登陆表单数据的FORM类
     * @author LanP
     * @since 2012年4月11日23:07:09
     * @version v1.0
     */
    @SuppressWarnings("serial")
    public class LoginActionForm extends ActionForm {
    	private String userName;
    	
    	private String passWord;
    	
    	public String getUserName() {
    		return userName;
    	}
    	public void setUserName(String userName) {
    		this.userName = userName;
    	}
    	public String getPassWord() {
    		return passWord;
    	}
    	public void setPassWord(String passWord) {
    		this.passWord = passWord;
    	}
    }

8、新建LoginAction.java

package com.lanp.webapp.action;
    
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    
    import org.apache.struts.action.Action;
    import org.apache.struts.action.ActionForm;
    import org.apache.struts.action.ActionForward;
    import org.apache.struts.action.ActionMapping;
    
    import com.lanp.webapp.form.LoginActionForm;
    /**
     * 处理登陆的Action类
     * @author LanP
     * @since 2012年4月11日23:07:09
     * @version v1.0
     */
    public class LoginAction extends Action {
    
    	@Override
    	public ActionForward execute(ActionMapping mapping, ActionForm form,
    			HttpServletRequest request, HttpServletResponse response)
    			throws Exception {
    		String path = "error";
    		LoginActionForm loginActionForm = (LoginActionForm)form;
    		String userName = loginActionForm.getUserName();
    		String passWord = loginActionForm.getPassWord();
    		
    		if(null != userName && "admin".equals(userName) && null != passWord && "admin".equals(passWord)) {
    			path = "success";
    			request.setAttribute("userName", userName);
    		} else {
    			path = "error";
    		}
    		return mapping.findForward(path);
    	}
    	
    }

9、配置struts-config.xml

<?xml version="1.0" encoding="UTF-8"?>
    <!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN" "http://struts.apache.org/dtds/struts-config_1_2.dtd">
    
    <struts-config>
    	<form-beans>
    		<form-bean name="loginActionForm" type="com.lanp.webapp.form.LoginActionForm">
    		</form-bean>
    	</form-beans>
    
    	<action-mappings>
    		<action path="/login"
    			type="com.lanp.webapp.action.LoginAction"
    			name="loginActionForm"
    			scope="request">
    			<forward name="success" path="/jsp/loginSucces.jsp" />
    			<forward name="error" path="/jsp/loginError.jsp" />
    		</action>
    	</action-mappings>
    </struts-config>

OK，TKS！