python中报错：'int' object is not callable error occur的解决方案

r囧r小猫 2022-06-07 01:37 286阅读 0赞

最近在学习python的相关知识，在写下面一段代码的时候报了一个错误：

def maxArea(height):
        max = 0
        for k in range(len(height)):
            if k + 1 < len(height):
                for m in range(k + 1, len(height)):
                    t = min(height[k], height[m])
                    c = t * abs(m - k)
                    max = max(max, c)
        return max
    
    print(maxArea([1, 1]))

报错如下：

TypeError: 'int' object is not callable

这里其实是自己新建的max变量与系统内嵌的max函数产生了冲突，把自己的变量修改为maxs，即可，如下：

def maxArea(height):
        maxs = 0
        for k in range(len(height)):
            if k + 1 < len(height):
                for m in range(k + 1, len(height)):
                    t = min(height[k], height[m])
                    c = t * abs(m - k)
                    maxs = max(maxs, c)
        return maxs
    
    
    print(maxArea([1, 1]))

结果是：

所以在命名的时候注意不能和自己使用的系统函数重名，切勿再犯这样的错误，特此记录~

参考：[https://stackoverflow.com/questions/11201801/why-does-the-int-object-is-not-callable-error-occur-when-using-the-sum-funct][https_stackoverflow.com_questions_11201801_why-does-the-int-object-is-not-callable-error-occur-when-using-the-sum-funct]

[https_stackoverflow.com_questions_11201801_why-does-the-int-object-is-not-callable-error-occur-when-using-the-sum-funct]: https://stackoverflow.com/questions/11201801/why-does-the-int-object-is-not-callable-error-occur-when-using-the-sum-funct