开心一下-换汽水问题

水深无声 2022-06-05 12:26 130阅读 0赞

> 一个锻炼脑力的脑筋急转弯

![换汽水][SouthEast]

10块买5瓶汽水，5瓶汽水5个盖子5个空瓶。。。
    好麻烦，写个程序吧

要点：分析出循环条件

#include <iostream>
    
    /* run this program using the console pauser or add your own getch, system("pause") or input loop */
    
    
    int main(int argc, char** argv) {
    
        int bottle=0,bottle_cap=0,empty_bottle=0;
        int num=0,money=0;
        printf("Please input your money :\n");
    
        while(scanf("%d",&money)==1)
        {           
            printf("Now the money you have is %d $!\n",money);
            bottle = money/2;
            int temp=0,temp_cap=0,temp_empty=0;
    
            bottle_cap = bottle;//5个盖 
            empty_bottle = bottle;//5个瓶子 
            num += bottle;//喝了5瓶 
    
            while(bottle_cap/4 >0 || empty_bottle/2>0)
            {   
                //处理瓶盖 bottle_cap
                temp_cap += bottle_cap/4;
                bottle_cap=bottle_cap%4;
                temp_empty += empty_bottle/2;
                empty_bottle=empty_bottle%2;
                temp = (temp_empty+temp_cap);
                num += temp;
    
                empty_bottle += temp;
                bottle_cap += temp;
    
                temp_cap = 0;   
                temp_empty = 0;
                temp=0;          
            }
            printf("According to your money...\n");
            printf("you can buy %d bottles'drink\n",num);
            num = 0;    
        }   
        return 0;
    }

实验现象预设：  
![这里写图片描述][SouthEast 1]

[SouthEast]: /images/20220605/2d2a07afe13a48fc937d33bf6dc21bab.png
[SouthEast 1]: /images/20220605/c6e4039a6ee4449f9205bc9e0db3f9ee.png