ACM-ICPC北京赛区2017网络同步赛 (题目6 : Secret Poems)

怼烎@ 2022-06-05 05:50 193阅读 0赞

### \#1632 : Secret Poems ###

时间限制: 1000ms

单点时限: 1000ms

内存限制: 256MB

### 描述 ###

The Yongzheng Emperor (13 December 1678 – 8 October 1735), was the fifth emperor of the Qing dynasty of China. He was a very hard-working ruler. He cracked down on corruption and his reign was known for being despotic, efficient, and vigorous.

Yongzheng couldn’t tolerate people saying bad words about Qing or him. So he started a movement called “words prison”. “Words prison” means literary inquisition. In the famous Zhuang Tinglong Case, more than 70 people were executed in three years because of the publication of an unauthorized history of the Ming dynasty.

In short, people under Yongzheng’s reign should be very careful if they wanted to write something. So some poets wrote poems in a very odd way that only people in their friends circle could read. This kind of poems were called secret poems.

A secret poem is a N×N matrix of characters which looks like random and meaning nothing. But if you read the characters in a certain order, you will understand it. The order is shown in figure 1 below:

![f.png][]

figure 1                                                           figure 2

Following the order indicated by arrows, you can get “THISISAVERYGOODPOEMITHINK”, and that can mean something.

But after some time, poets found out that some Yongzheng’s secret agent called “Mr. blood dripping” could read this kind of poems too. That was dangerous. So they introduced a new order of writing poems as shown in figure 2. And they wanted to convert the old poems written in old order as figure1 into the ones in new order. Please help them.

### 输入 ###

There are no more than 10 test cases.

For each test case:

The first line is an integer N( 1 <= N <= 100), indicating that a poem is a N×N matrix which consist of capital letters.

Then N lines follow, each line is an N letters string. These N lines represent a poem in old order.

### 输出 ###

For each test case, convert the poem in old order into a poem in new order.

样例输入

5
    THSAD 
    IIVOP 
    SEOOH 
    RGETI 
    YMINK
    2
    AB
    CD
    4
    ABCD
    EFGH
    IJKL
    MNOP

样例输出

THISI
    POEMS
    DNKIA
    OIHTV
    OGYRE
    AB
    DC
    ABEI
    KHLF
    NPOC
    MJGD

\#include<cstdio>  
\#include<cstring>  
\#include<string>  
\#include<algorithm>  
using namespace std;  
int main()\{

int n,x,ok,y;  
    char map1\[101\]\[101\];  
    char map2\[101\]\[101\];  
    char str\[10001\];  
    while(~scanf("%d",&n))\{  
    for(int i=0;i<n;i++)\{  
        scanf("%s",map1\[i\]);  
    \}

for(int i=0;i<n;i++)\{  
        for(int j=0;j<n;j++)\{  
            map2\[i\]\[j\]='@';  
        \}  
        map2\[i\]\[n\]='\\0';  
    \}  
   // printf("----------\\n");  
    str\[0\]=map1\[0\]\[0\];  
    ok=0,x=0,y=0;  
    int len=1;  
  while(len<n\*n) \{  
   if(x==0&&ok==0) \{  
    if(y+1<n) \{  
    y++;  
    ok=1;  
    \}  
    else\{  
     x++;  
     ok=1;  
    \}  
   \}  
   else if(y==0&&ok==1) \{  
    if(x+1<n) \{  
    x++;  
    ok=0;  
    \}  
    else \{  
     y++;  
     ok=0;  
    \}  
   \}  
   else \{  
    if(ok==1) \{  
     if(x+1<n&&y-1>=0) \{  
     x++;  
     y--;  
     ok=1;  
     \}else \{  
      y++;  
      ok=0;  
     \}  
    \}  
    else if(ok==0) \{  
     if(x-1>=0&&y+1<n) \{  
     x--;  
     y++;  
     ok=0;  
     \}else \{  
      x++;  
      ok=1;  
     \}  
    \}  
   \}  
   //printf("%d %d %d\\n",x,y,ok);  
   str\[len\]=map1\[x\]\[y\];  
   len++;  
        \}  
        str\[len\]='\\0';  
        x=y=0;  
  int s=0;  
//  for(int i=0;i<16;i++)\{  
//            str\[i\]=char('A'+i);  
//  \}  
  //printf("%s\\n",str);  
  for(int i=0;i<strlen(str);) \{  
   while(y<n && map2\[x\]\[y\]=='@') \{  
    map2\[x\]\[y\]=str\[i++\];  
    y++;  
   \}  
   y=y-1;  
   x=x+1;  
   while(x<n &&map2\[x\]\[y\]=='@')\{  
    map2\[x\]\[y\]=str\[i++\];  
             x++;  
   \}  
   y=y-1;  
   x=x-1;  
   while(y>=0 &&map2\[x\]\[y\]=='@')\{  
    map2\[x\]\[y\]=str\[i++\];  
    y--;  
   \}  
   x=x-1;  
   y=y+1;  
   while(x>=0&&map2\[x\]\[y\]=='@')\{  
    map2\[x\]\[y\]=str\[i++\];  
    x--;  
   \}  
   y=y+1;  
   x=x+1;  
  \}

for(int i=0;i<n;i++) \{  
   for(int j=0;j<n;j++) \{  
    printf("%c",map2\[i\]\[j\]);  
   \}  
   printf("\\n");  
  \}  
    \}  
    return 0;  
\}

[f.png]: /images/20220605/d2fd61ca7eee454aa8375739e0506e92.png