leetcode 609. Find Duplicate File in System 寻找重复内容+stringstream很好示范

- 日理万妓 2022-06-03 05:12 140阅读 0赞

Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their paths.

A group of duplicate files consists of at least two files that have exactly the same content.

A single directory info string in the input list has the following format:

“root/d1/d2/…/dm f1.txt(f1\_content) f2.txt(f2\_content) … fn.txt(fn\_content)”

It means there are n files (f1.txt, f2.txt … fn.txt with content f1\_content, f2\_content … fn\_content, respectively) in directory root/d1/d2/…/dm. Note that n >= 1 and m >= 0. If m = 0, it means the directory is just the root directory.

The output is a list of group of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format:

“directory\_path/file\_name.txt”

Example 1:  
Input:  
\[“root/a 1.txt(abcd) 2.txt(efgh)”, “root/c 3.txt(abcd)”, “root/c/d 4.txt(efgh)”, “root 4.txt(efgh)”\]  
Output:  
\[\[“root/a/2.txt”,”root/c/d/4.txt”,”root/4.txt”\],\[“root/a/1.txt”,”root/c/3.txt”\]\]  
Note:  
No order is required for the final output.  
You may assume the directory name, file name and file content only has letters and digits, and the length of file content is in the range of \[1,50\].  
The number of files given is in the range of \[1,20000\].  
You may assume no files or directories share the same name in the same directory.  
You may assume each given directory info represents a unique directory. Directory path and file info are separated by a single blank space.  
Follow-up beyond contest:  
Imagine you are given a real file system, how will you search files? DFS or BFS?  
If the file content is very large (GB level), how will you modify your solution?  
If you can only read the file by 1kb each time, how will you modify your solution?  
What is the time complexity of your modified solution? What is the most time-consuming part and memory consuming part of it? How to optimize?  
How to make sure the duplicated files you find are not false positive?

这道题题意很简单，但是假如要是使用字符串分割来做的话相当麻烦，还是C++的stringstream好用，直接遍历然后分解即可。

建议和[leetcode 592. Fraction Addition and Subtraction C++的stringstream的一个很好的示例][leetcode 592. Fraction Addition and Subtraction C_stringstream] 一起学习

代码如下：

#include <iostream>
    #include <vector>
    #include <map>
    #include <set>
    #include <queue>
    #include <stack>
    #include <string>
    #include <climits>
    #include <algorithm>
    #include <sstream>
    #include <functional>
    #include <bitset>
    #include <numeric>
    #include <cmath>
    #include <regex>
    
    using namespace std;
    
    class Solution 
    {
    public:
        vector<vector<string>> findDuplicate(vector<string>& paths) 
        {
            vector<vector<string>> res;
            map<string, vector<string>> mmp;
            for (string path : paths)
            {
                stringstream ss(path);
                string pre, file;
                ss >> pre;
                while (ss >> file)
                {
                    int i = file.find_last_of('(');
                    string dir = pre + "/" + file.substr(0, i);
                    string context = file.substr(i+1,file.length()-i-2);
                    mmp[context].push_back(dir);
                }
            }
    
            for (auto i : mmp)
            {
                if (i.second.size() > 1)
                    res.push_back(i.second);
            }
            return res;
        }
    };

[leetcode 592. Fraction Addition and Subtraction C_stringstream]: http://blog.csdn.net/jackzhang_123/article/details/78837215