(PTA详解）L1-003. 个位数统计

Dear 丶 2022-06-03 00:55 116阅读 0赞

![20171213155958165][]

**思路：本题的坑点是不超过1000位的整数，所以也便于后期的求出现的个数，采用字符数组开1000空间方式。代码就比较简单了，相信大家能看懂。**

**代码如下：**

#include <iostream>
    #include <string.h>
    
    using namespace std;
    
    int main()
    {
        char a[1000];
    
        while(cin>>a)
        {
            int n0=0,n1=0,n2=0,n3=0,n4=0,n5=0,n6=0,n7=0,n8=0,n9=0;//赋初值
            int m;
            m=strlen(a);//求出字符数组长度
            for(int i=0;i<m;i++)
            {
                 if(a[i]=='0')
                {
                    n0++;
                }
                else if(a[i]=='1')
                {
                    n1++;
                }
                else if(a[i]=='2')
                {
                    n2++;
                }
                else if(a[i]=='3')
                {
                    n3++;
                }
                else if(a[i]=='4')
                {
                    n4++;
                }
                else if(a[i]=='5')
                {
                    n5++;
                }
                else if(a[i]=='6')
                {
    
                    n6++;
                }
                else if(a[i]=='7')
                {
                    n7++;
                }
                else if(a[i]=='8')
                {
                    n8++;
                }
                else if (a[i]=='9')
                {
                    n9++;
                }
            }
            if(n0)
            {
            cout<<"0:"<<n0<<endl;
            }
            if(n1)
            {
            cout<<"1:"<<n1<<endl;
            }
            if(n2)
            {
            cout<<"2:"<<n2<<endl;
            }
            if(n3)
            {
            cout<<"3:"<<n3<<endl;
            }
            if(n4)
            {
            cout<<"4:"<<n4<<endl;
            }
            if(n5)
            {
            cout<<"5:"<<n5<<endl;
            }
            if(n6)
            {
            cout<<"6:"<<n6<<endl;
            }
            if(n7)
            {
            cout<<"7:"<<n7<<endl;
            }
            if(n8)
            {
            cout<<"8:"<<n8<<endl;
            }
            if(n9)
            {
            cout<<"9:"<<n9<<endl;
            }
    
        }
        return 0;
    }

[20171213155958165]: /images/20220603/f895716e562e4cf8897accd6261ae750.png