1031. Hello World for U (20)

古城微笑少年丶 2022-05-31 09:48 150阅读 0赞

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as:

h  d
    e  l
    l  r
    lowo

That is, the characters must be printed in the original order, starting top-down from the left vertical line with n 1 characters, then left to right along the bottom line with n 2 characters, and finally bottom-up along the vertical line with n 3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n 1 = n 3 = max \{ k| k <= n 2 for all 3 <= n 2 <= N \} with n 1 \+ n 2 \+ n 3 \- 2 = N.

**Input Specification:**

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

**Output Specification:**

For each test case, print the input string in the shape of U as specified in the description.

**Sample Input:**

helloworld!

**Sample Output:**

h   !
    e   d
    l   l
    lowor

--------------------

题目大意：

给定任意N个字符的字符串，要求你将字符组成u的形状，例如，“helloworld!”可以打印为：  
h d  
e l  
l r  
lowo  
也就是说，字符必须以原始顺序打印出来，从左侧的垂直行开始打印n1个字符，然后沿着底部打印一行n2个字符，最后沿着底部垂直向上打印n3个字符。而且，我们希望U尽可能的成方形，也就是说，他必须满足n1=n3=max\{k|k<=n2,所有的3<=n2<=N\},n1+n2+n3-2=N.  
输入规格：  
每一个输入文件包含一个测试用例。每个测试用例包含一个不小于5也不大于80个字符的字符串。该字符串中不包含空格。  
输出规格：  
对于每个测试用例，按照描述中指定的U的形状打印输入字符串。

代码：

#include<stdio.h>
    #include<string.h>
    int main()
    {
        int i,j,n,m,k,t,n1,n2;
        char str[100];
        scanf("%s",str);
        n=strlen(str);
        m=(n+2)/3;
        k=n-2*(m-1)-2;
        for(i=0;i<m-1;i++)
            {
                printf("%c",str[i]);
                for(j=0;j<k;j++)
                    printf(" ");
                printf("%c\n",str[n-i-1]);
    
            }
            for(i=m-1;i<n-m+1;i++)
                printf("%c",str[i]);
        return 0;
    }