简单枚举类型——植物与颜色

谁践踏了优雅 2022-05-29 10:08 208阅读 0赞

### 简单枚举类型——植物与颜色 ###

Time Limit: 1000 ms Memory Limit: 65536 KiB

[Submit][] [Statistic][]

#### Problem Description ####

请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color，根据输入的颜色名称，输出以下六种植物花朵的颜色：

Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中，例如输入purple，请输出I don't know about the color purple.

#### Input ####

输入数据有多行，每行有一个字符串代表颜色名称，颜色名称最多30个字符，直到文件结束为止。

#### Output ####

输出对应颜色的植物名称，例如：Bluebells are blue. 如果输入的颜色名称不在枚举类型color中，例如purple, 请输出I don't know about the color purple.

#### Sample Input ####

blue
    yellow
    purple

#### Sample Output ####

Bluebells are blue.
    Sunflower are yellow.
    I don't know about the color purple.

package hello;
    import java.util.Scanner;
    enum Color{
    	red("Rose", "red"),                      //建立对应的枚举类型
    	orange("Poppies", "orange"), 
    	yellow("Sunflower","yellow"), 
    	green("Grass", "green"), 
    	blue("Bluebells", "blue"), 
    	violet("Violets", "violet");
    	
    	String name;
    	String color;
    	
    	Color(String name, String color){    //构造方法
    		this.name = name;
    		this.color = color;
    	}
    	public String toString() {          //重写toSting方法
    		return name+" are "+color+".";
    	}
    }
    public class Main {  
       
        public static void main(String[] args) {  
            Scanner cin = new Scanner(System.in);  
            int flag = 1;
            while(cin.hasNext()) {
            	String incolor = cin.next();
            	/*Color color = Color.valueOf(incolor);     //本来想通过转化之后判断一个该颜色有没有在枚举序列中，当时如果没在序列中
            	for(Color a:color.values()) {           //valueOf函数就会抛出异常，程序没法执行，所以用try来实现
            		if(a.equals(color)) {
            			flag = 0;
            			break;
            		}
            	}
            	if(flag == 0) {
            		System.out.println(color);
            	}
            	else {
            		System.out.println("I don't know about the color "+incolor+".");
            	}*/
            	try{                             //如果输入的颜色不在对应的颜色序列当中，就会抛出异常
    				Color color = Color.valueOf(incolor);
    				System.out.println(color);
    			}
    			catch(Exception e){
    				System.out.println("I don't know about the color "+incolor+".");
    			}
            }
            cin.close();
        }  
    }

[Submit]: https://acm.sdut.edu.cn/onlinejudge2/index.php/Home/Contest/contestsubmit/cid/2434/pid/1959.html
[Statistic]: https://acm.sdut.edu.cn/onlinejudge2/index.php/Home/Contest/conteststatus/cid/2434/pid/1959.html