习题 9.5 有10个学生,每个学生的数据包括学号、姓名、3门课程的成绩,从键盘输入10个学生数据,要求输出3门课程总平均成绩,以及最高分的学生的数据(包括学号、姓名、3门课程成绩、平均分数)。
C程序设计(第四版) 谭浩强 习题9.5 个人设计
习题 9.5 有10个学生,每个学生的数据包括学号、姓名、3门课程的成绩,从键盘输入10个学生数据,要求输出3门课程总平均成绩,以及最高分的学生的数据(包括学号、姓名、3门课程成绩、平均分数)。
代码块:
方法1:
#include <stdio.h>
struct student
{
int num;
char name[10];
float score[3];
float aver;
} stu[10];
void input(struct student s[], int n);
void average(struct student s[], int n);
void high_score(struct student s[], int n);
int main()
{
input(stu, 10);
average(stu, 10);
high_score(stu, 10);
return 0;
}
void input(struct student s[], int n)
{
int i, j;
for (i=0; i<n; i++){
printf("Please enter No.%d student num name score: ", i+1);
scanf("%d %s", &s[i].num, s[i].name);
for (j=0; j<3; scanf("%f", &s[i].score[j++]));
}
}
void average(struct student s[], int n)
{
int i, j;
float sum;
for (i=0, sum=0.0; i<n; i++)
for (j=0; j<3; sum+=s[i].score[j++]);
printf("Average=%.2f\n", sum/n);
}
void high_score(struct student s[], int n)
{
int i, j;
float sum;
struct student temp;
for (i=0; i<n; i++){
for (j=0, sum=0.0; j<3; sum+=s[i].score[j++]);
s[i].aver=sum/3;
}
for (i=0; i<n; i++)
for (j=i+1; j<n; s[i].aver<s[j].aver ? temp=s[i], s[i]=s[j], s[j]=temp, j++ : j++);
printf("The highest student info: %d %-5s ", s[0].num, s[0].name);
for (i=0; i<3; printf("%.2f ", s[0].score[i++]));
printf("%.2f\n", s[0].aver);
}
方法2:
#include <stdio.h>
#include <stdlib.h>
struct Student{
int num;
char name[20];
float score[3];
};
void input(Student *st);
void print(Student *st);
int main()
{
Student *stu=(Student*)malloc(3*sizeof(Student));
input(stu);
print(stu);
system("pause");
return 0;
}
void input(Student *st)
{
int i;
Student *p;
for (p=st, i=0; p<st+3; p++, i++){
printf("Please enter No.%d student info: ", i+1);
scanf("%d %s", &p->num, p->name);
for (i=0; i<3; scanf("%f", &p->score[i++]));
}
}
void print(Student *st)
{
int i, j;
float aver, sum[3], total, max;
Student *p;
for (p=st, i=0, total=0; p<st+3; p++, i++){
for (j=0, sum[i]=0; j<3; sum[i]+=p->score[j++]);
total+=sum[i]/3;
}
aver=total/3;
printf("Total Average: %.2f\n", aver);
for (i=0, max=sum[i]; i<3; i++)
if (sum[i]>max){
max=sum[i];
j=i;
}
printf("The highest score student info: %d %s ", (st+j)->num, (st+j)->name);
for (i=0; i<3; printf("%.2f ", (st+j)->score[i++]));
printf("\n");
}
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