python从入门到实践第七章习题（高级编程技术 week4-1）

柔光的暖阳◎ 2022-05-28 01:07 168阅读 0赞

# python从入门到实践 第七章习题 （高级编程技术 week4-1） #

这一节课主要讲的是在python中用户输入的处理以及while循环的编写。

## 7.1 函数input() ##

需要注意的一点是，input()函数获取的用户输入一般都是字符串形式的，需要对数据进行进一步的处理（如课本示例中的int()函数将字符串转成数字）。

### 7-1 汽车租赁 ###

print('Whick kind of cars do you want?')
    car=('please enter the car you want : ')
    print('Let me see if I can find you a Subaru')

### 7-3 10的整数倍 ###

number = input('Please enter an number : ')
    number = int(number)
    if number % 10 == 0:
        print(number, ' is not an integer multiple of ten.')
    else:
        print(number, ' is an integer multiple of ten.')

## 7.2 while循环的编写 ##

在这一张，出现了三个新的关键字：while，break，continue

### 7-4 披萨配料 ###

message = ''
    while 1:
        message = input('Please enter ingredients for pizza')
        if message == 'quit'
            break
        else:
            print('We will add this ingredients in pizza!')

### 7-5 电影票 ###

active = True
    while active：
        age = input('Please enter your age : ')
        age = int(age)
        if age < 3:
            print('You are free!')
        elif 3 <= age && age <= 12:
            print('Your fee is ten dollars')
        else:
            print('Your fee is fifteen dollars')

## 7.3 使用while循环处理列表和字典 ##

笔记：for循环是一种遍历列表的有效方式，但在for循环中不应修改列表，否则将导致Python难以跟踪其中的元素。要在遍历列表的同时对其进行修改，可使用while循环。通过将while循环同列表和字典结合起来使用，可收集、存储并组织大量输入，供以后查看和显示。

### 7-8 熟食店 ###

sandwich_orders = ['sandwich1','sandwich2', 'sandwich3']
    
    finished_sandwiches = []
    
    while sandwich_orders:
        make_sandwich = sandwich_orders.pop()
        print('I made your ', make_sandwich,'.')
        finished_sandwiches.append(make_sandwich)
    
    for finished_sandwich in fornished_sandwich:
        print(finished_sandwich, ' has finished.')

### 7-10 梦想的度假胜地 ###

result = {}
    
    active = True
    
    while active:
        name = input('Please enter your name')
        respone = input('If you could visit on place in the world, where would you go?')
        result[name] = respone
        q = inpur('Quit? [N]/Y')
        if q == 'Y'
            break
    
    for name, respone in result.items():
        print(name.title(), ' : ', respone)