C#序列化XML文件

古城微笑少年丶 2022-05-27 02:59 150阅读 0赞

# C\#序列化XML文件 #

本Markdown编辑器使用\[StackEdit\]\[6\]修改而来，用它写博客，将会带来全新的体验哦：

*  **序列化类**
 *  **方法调用**

--------------------

## 序列化类 ##

using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    using System.IO;
    using System.Threading.Tasks;
    using System.Windows.Forms;
    using System.Xml.Serialization;
    
    namespace Bnu.Coastal.SysManage
    {
        public class Achieves
        {
            //序列化对象的集合
            public List<ImgFile> imgFiles = new List<imgFile>();
    
            //正序列化：从对象到XML
            public void Serializer(string filename)
            {
                using (FileStream fs = new FileStream(filename, FileMode.Create, FileAccess.Write, FileShare.Read))
                {
                    XmlSerializer xs = new XmlSerializer(typeof(Achieves));
                    xs.Serialize(fs, this);
                }
            }
            //反序列化：从XML到对象
            public static Achieves Deserialize(string filename)
            {
                Achieves aa = null;
                 using (FileStream fs = new FileStream(filename, FileMode.Open))
                {
                    XmlSerializer xs = new XmlSerializer(typeof(Achieves));
                    aa = xs.Deserialize(fs) as Achieves;           
                }
                return aa;
            }       
        }
        //定义序列化对象
        public class ImgFile
        {
            public string fileId { get; set; }
            public string fileType { get; set; }
            public string fileName { get; set; }   
        }
    }

## 正序列化 ##

string xmlFile = "filePath";
    List<ImgFile> imgFileList = Achieves.Deserialize(xmlFile).imgFiles;

## 反序列化 ##

string xmlFile = "filePath";
    var ach = Achieves.Deserialize(xmlFile);
    List<ImgFile> imgFileList = ach.imgFiles;
    ImgFile img = new ImgFile();
    imgFileList.Add(img);
    ach.Serializer(xmlFile);