获取微信openid（静默式不需要用户同意）

素颜马尾好姑娘i 2022-05-23 13:04 595阅读 0赞

### 1.微信公众号 -->功能设置-->配置网页授权域名 ###

### 2.准备2个url，一个访问地址获取code，另一个获取openid ###

![70][]

String url = "https://open.weixin.qq.com/connect/oauth2/authorize"
    				+ "?appid=APPID"
    				+ "&redirect_uri=REDIRECT_URI"
    				+ "&response_type=code"
    				+ "&scope=snsapi_base"
    				+ "&state=STATE"
    				+ "#wechat_redirect";

![70 1][]

String url = "https://api.weixin.qq.com/sns/oauth2/access_token"
    				+ "?appid=AppId"
    				+ "&secret=AppSecret"
    				+ "&code=CODE"
    				+ "&grant_type=authorization_code";

### 3.用户访问此接口  ###

@GetMapping("/getCode")
    public void getCode(HttpServletRequest request, HttpServletResponse response) throws ClientProtocolException, IOException {
        String url = WxUtils.getOpenIdUrl("xiaoming");
        System.out.println("微信网址："+url);
        response.sendRedirect(url);
    }

@GetMapping("/getOpenId")
    public Map<String,Object> getOpenId(HttpServletRequest request, HttpServletResponse response) throws ClientProtocolException, IOException {
        Map<String,Object> map = new HashMap<String,Object>();  
        String code = request.getParameter("code");//微信会返回code值，用code获取openid
        String openId = WxUtils.getOpendId(code);
        map.put("openId", openId);
        return map;}

### 4.getOpenId(code)方法介绍 ###

public static String getopendid(String code) throws ParseException, IOException {
    		
    		String appid = "xxx";
    		String secret = "xxx";
    		
    		String url = "https://api.weixin.qq.com/sns/oauth2/access_token"
    				+ "?appid=AppId"
    				+ "&secret=AppSecret"
    				+ "&code=CODE"
    				+ "&grant_type=authorization_code";
    		url = url.replace("AppId", appid)
        		.replace("AppSecret", secret)
                    .replace("CODE", code);
    		
    		HttpGet get = HttpClientConnectionManager.getGetMethod(url);
    		HttpResponse response = httpclient.execute(get);
    		String jsonStr = EntityUtils.toString(response.getEntity(), "utf-8");
    		JSONObject jsonTexts = (JSONObject) JSON.parse(jsonStr);
    		
    		String openid = "";
    		if (jsonTexts.get("openid")!=null) {
    			openid = jsonTexts.get("openid").toString();
    		}
    		return openid;
    	}

[70]: /images/20220523/59751eb1f28f456babb10767864003eb.png
[70 1]: /images/20220523/972b5271612c42b59850208995c1840d.png