映射_将obj持有的属性拼接字符串

小咪咪 2022-05-23 03:06 109阅读 0赞

先创建一个Joint类，写入showInfo方法：

public class Obj {
    	private String name;
    	private String gender;
    	private Integer age;
    	public Obj() {
    		super();
    	}
    	public Obj(String name, String gender, Integer age) {
    		super();
    		this.name = name;
    		this.gender = gender;
    		this.age = age;
    	}
    	public String getName() {
    		return name;
    	}
    	public void setName(String name) {
    		this.name = name;
    	}
    	public String getGender() {
    		return gender;
    	}
    	public void setGender(String gender) {
    		this.gender = gender;
    	}
    	public Integer getAge() {
    		return age;
    	}
    	public void setAge(Integer age) {
    		this.age = age;
    	}
    	public void showInfo() {
    		System.out.println(this.getName()+"---"+this.getGender()+"---"+this.getAge());
    	}
    }

以下是三种方法：

（1）通过属性调取方法实现字符串拼接：

public static void main(String[] args) throws Exception {
    		Class c=Obj.class;
    		//此方法为通过属性调取方法
    		Object o=c.newInstance();
    		Field jName=c.getDeclaredField("name");//获取属性
    		Field jSex=c.getDeclaredField("sex");
    		jName.setAccessible(true);//取消访问修饰符的限制
    		jName.set(o,"吴亦凡");
    		jSex.setAccessible(true);
    		jSex.set(o,"28");
    		
    		Method show=c.getDeclaredMethod("showInfo");
    		Object invo=show.invoke(o);
    		System.out.println(invo);
    	}

（3）通过构造器：

public static void main(String[] args) throws Exception {
    		Class c=Obj.class;
    		Constructor[] cons=c.getDeclaredConstructors();
    		for(Constructor con:cons){
    			Class[] paras=con.getParameterTypes();
    			if(paras.length!=0){
    				Obj obj=(Obj) con.newInstance(new Object[]{"成龙","男",68});
    				obj.showInfo();
    			}
    		}
    	}

console:

成龙---男---68