5.3 数组初始化

柔情只为你懂 2022-05-20 07:24 217阅读 0赞

![70][]![70 1][]![70 2][]![70 3][]![70 4][]

#include<iostream>
    #include<cstdio>
    int main()
    {
    	int n;
    	scanf("%d", &n);
    	switch(n)
    	{
    		case 1://如果n==1 
    			printf("Monday.");//输出Monday 
    			break;//跳出整个switch循环 
    		case 2:
    			printf("Tuesday.");
    			break;
    		case 3:
    			printf("Wednesday.");
    			break;
    		case 4:
    			printf("Thursday.");
    			break;
    		case 5:
    			printf("Friday.");
    			break;
    		case 6:
    			printf("Saturday.");
    			break;
    		case 7:
    			printf("Sunday.");
    			break;
    		default:
    			printf("Illegal.");
    	}
    	return 0;
    }

![70 5][]

#include<iostream>
    #include<cstring>
    using namespace std;
    string weekdays[]={"Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"};
    int main()
    {
    	int n;
    	cin >> n;
    	if(n < 1 || n > 7)
    		cout << "Illegal";
    	else
    		cout << weekdays[n-1];
    	return 0;
    }

![70 6][]![70 7][]![70 8][]![70 9][]

#include<iostream>
    using namespace std;
    int monthdays[13]={-1,31,28,31,30,31,30,31,31,30,31,30,31};
    int main()
    {
    	int year, month, day, days=0;
    	cin >> year >> month >> day;
    	for(int i = 2012; i < year; ++i)//算年一共有多少天 
    	{
    		if((i % 4 == 0 && i % 100 != 0) || i % 400 == 0)
    			days += 366;
    		else 
    			days += 365;
    	}
    	if((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)
    			monthdays[2] = 29;
    	for(int i = 1; i < month; ++i)//算不足一年的有几个月所有的天数 
    	{
    		days += monthdays[i];
    	} 
    	days += day;//算剩余的最后一个月的天数 
    	days -= 22;//减去第一年1月份的天数 
    	cout << days % 7 << endl;//用总的天数对7取余，就可以得到星期几了 
    	return 0;
    }

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