servlet如何获取json数据

朴灿烈づ我的快乐病毒、 2022-05-19 13:25 578阅读 0赞

<!DOCTYPE html>
    <html>
    <head>
    <meta charset="UTF-8">
    <title>Insert title here</title>
    
    <script src="https://cdn.bootcss.com/jquery/1.10.2/jquery.min.js" ></script>
    </head>
    <body>
    
    	<input type="button" value="获取" />
    
    </body>
    
    	<script>
    		
    	function get(){
    		
    		var url = "HelloStu";
    		 $.ajax({
    		        type: "get",
    		        url: url,
    //		      data: "para="+para,  此处data可以为 a=1&b=2类型的字符串 或 json数据。
    		        data: {
    		        	"name":"张三";
    		 			"age":18
    		        },
    		        cache: false,
    		        async : false,
    		        dataType: "json",
    		        success: function (data ,textStatus, jqXHR)
    		        {
    		            if("true"==data.flag){
    		               alert("合法！");
    		                return true;
    		            }else{
    		                alert("不合法！错误信息如下："+data.errorMsg);
    		                return false;
    		            }
    		        },
    		        error:function (XMLHttpRequest, textStatus, errorThrown) {      
    		            alert("请求失败！");
    		        }
    		     });
    		
    	}
    	
         $("input").bind("click",function(){
        	 
        	 get();
        	 
         })
     
    
    	</script>
    </html>

java中的代码是

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    		// TODO Auto-generated method stub
    //		response.setCharacterEncoding("gb2312");
    //		response.setContentType("application/json;charset=gb2312");
    		
    		String name = request.getParameter("name");
    		String age = request.getParameter("age");
    		System.out.println(name);
    		System.out.println(age);
    		
    	}

然后运行index.html，点击按钮，控制台就会打印数据：

张三
    18