PAT乙级(Basic Level)真题 1007 A除以B Java

朱雀 2022-05-16 09:05 129阅读 0赞

### **题目描述** ###

本题要求计算A/B，其中A是不超过1000位的正整数，B是1位正整数。你需要输出商数Q和余数R，使得A = B * Q + R成立。

### **输入描述:** ###

输入在1行中依次给出A和B，中间以1空格分隔。

### **输出描述:** ###

在1行中依次输出Q和R，中间以1空格分隔。

### **输入例子:** ###

123456789050987654321 7

### **输出例子:** ###

17636684150141093474 3

***我的代码：***

import java.math.BigInteger;  
import java.util.Scanner;

public class Main \{

public static void main(String\[\] args) \{  
        // TODO Auto-generated method stub  
        Scanner in=new Scanner(System.in);  
        BigInteger a=in.nextBigInteger();  
        BigInteger b=in.nextBigInteger();  
        in.close();  
        System.out.print(a.divide(b)+" ");  
        System.out.print(a.mod(b));  
    \}

***大佬的代码：***

`       `

`import java.util.Scanner;`

`/**  * Created by lang on 2016/1/18.  */ public class Main {     int R = 0;     public static void  main(String[] args) {         Scanner sc = new Scanner(System.in);         String A = sc.next();         int B = sc.nextInt();         bigDiv(A, B);     }     static void bigDiv(String A,int B){         StringBuffer Q = new StringBuffer();           char[] cA = A.toCharArray();         int r = 0;         int a = 0;         for (int i = 0; i < cA.length; i++) {             a = r * 10 + Integer.parseInt(String.valueOf(cA[i]));             Q.append(a/B);             r = a % B;         }         while (Q.charAt(0)=='0')Q.delete(0,1);         System.out.println(Q.toString()+" "+r);     }   }`

***另一位：***

`import` `java.util.Scanner;`

`public` `class` `Main {`

`    ``public` `static` `void` `main(String[] args) {`

`        ``Scanner in = ``new` `Scanner(System.in);`

`        ``try` `{`

`            ``String a = in.next();`

`            ``int` `b = in.nextInt();`

`            ``int` `s = ``0``;`

`            ``for` `(``int` `i = ``0``; i < a.length(); i++) {`

`                ``int` `n = a.charAt(i) - ``'0'``;`

`                ``s = s + n;`