混沌置乱演示

落日映苍穹つ 2022-05-15 01:39 152阅读 0赞

function zhiluanAll %对原始图像进行置乱 clear; clc; %os原始图像的路径 \[filename pathname\]=uigetfile('\*.bmp;\*.tiff;\*.tif', '读入图像'); os=\[pathname filename\]; o=imread(os); % figure,imshow(o); %计算原始图像的大小 \[m n\]=size(o); %l=zeros(m,n); l=linspace(0,0,m\*n); l(1)=0.98; for i=2:m\*n l(i)=1-2\*l(i-1)\*l(i-1); end % %对生成的混沌序列进行排序 % \[lsort lindex\]=sort(l); % t=linspace(0,0,m\*n); % t(1)=0.98; % for i=1:m\*n % t(i+1)=1-2\*t(i)\*t(i); % end % for i=1:m\*n % if (l(i)>=0) % l(i)=1; % else % l(i)=0; % end % end % l=~l; % subplot(2,2,2),imshow(l),title('混沌图像'); \[lsort,lindex\]=sort(l); %ozl =original zhi luan 表示置乱后的原始图像 ozl=zeros(m,n); for i=1:m\*n ozl(i)=o(lindex(i)); end % ozl=reshape(ozl,m,n); %%oo =original fu yuan ofy=zeros(m,n); for i=1:m\*n ofy(lindex(i))=ozl(i); end h= waitbar(0,'程序处理中，请耐心等待。。。'); for i=1:100, % computation here % waitbar(i/100) end close(h) ; %%%%%%%%%%%%%%%%%%错误的初始密钥 l=linspace(0,0,m\*n); l(1)=0.9800001; for i=2:m\*n l(i)=1-2\*l(i-1)\*l(i-1); end \[lsort,lindex\]=sort(l); ofyError=zeros(m,n); for i=1:m\*n ofyError(lindex(i))=ozl(i); end %%%%%%%%%%%%%%%%%%错误的初始密钥 subplot(2,2,1),imshow(o);%,title('原始图像'); title('(a)原始图像','position',\[33.5 80.28\]); subplot(2,2,2),imshow(ozl,\[\]);%,title('加密图像'); title('(b)加密图像','position',\[33.5 80.28\]); subplot(2,2,3),imshow(ofy,\[\]);%,title('复原图像'); title('(c) 正确密钥解密','position',\[33.5 80.28\]); subplot(2,2,4),imshow(ofyError,\[\]);%,title('复原图像'); title('(d) 错误密钥解密','position',\[33.5 80.28\]);

[![chaoticDemo2e][]][chaoticDemo2e 1]

[chaoticDemo2e]: /images/20220515/98a6048a3111495397366d9854e706f8.png
[chaoticDemo2e 1]: http://hi.csdn.net/attachment/201012/15/0_1292395100kxZC.gif