Linux Shell获取正在执行脚本的绝对路径

小鱼儿 2022-05-15 00:26 434阅读 0赞

使用脚本：

BASE_PATH=$(cd `dirname $0`;pwd)
    echo "base_path is $BASE_PATH"

或者

DIR_PATH="$( cd "$( dirname "${BASH_SOURCE[0]}" )" >/dev/null && pwd )"
    echo "dir_path is $DIR_PATH"

我们在HOME目录下，建立文件夹a，b，在a目录下创建**test.sh**，在HOME目录下执行**test.sh**脚本，执行结果如下：  
![这里写图片描述][70]

注意，这种方法一般情况都可以正确获取，但如果执行脚本本身是符号链接，那这种方法就不大奏效，我们测试一下，我们在b目录下创建一个符号链接**ln\_test.sh**，指向a目录下的**test.sh**  
![这里写图片描述][70 1]  
执行b目录下的**ln\_test.sh**，得到结果如下：  
![这里写图片描述][70 2]

为了解决符号链接问题，我们可以用以下脚本

SOURCE="${BASH_SOURCE[0]}"
    while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
      DIR="$( cd -P "$( dirname "$SOURCE" )" >/dev/null && pwd )"
      SOURCE="$(readlink "$SOURCE")"
      [[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
    done
    DIR="$( cd -P "$( dirname "$SOURCE" )" >/dev/null && pwd )"

执行a目录下的**test.sh**脚本，得到结果如下：  
![这里写图片描述][70 3]  
执行b目录下的**ln\_test.sh**，得到结果如下：  
![这里写图片描述][70 4]

[https://stackoverflow.com/questions/59895/getting-the-source-directory-of-a-bash-script-from-within][https_stackoverflow.com_questions_59895_getting-the-source-directory-of-a-bash-script-from-within]

[70]: /images/20220515/1dd65dc0f79745a8b46ca8f343fadf79.png
[70 1]: /images/20220515/43edb67645f1403c8f6fc04a16d3281c.png
[70 2]: /images/20220515/c4aa6cd7a4984da792d03c7d4b25b053.png
[70 3]: /images/20220515/de726f0cc2d94362af7751558e6f7b09.png
[70 4]: /images/20220515/70a640dfc521432c97e5a5f99bf61525.png
[https_stackoverflow.com_questions_59895_getting-the-source-directory-of-a-bash-script-from-within]: https://stackoverflow.com/questions/59895/getting-the-source-directory-of-a-bash-script-from-within