GPS坐标转百度坐标 偏执的太偏执、 2022-05-01 13:18 366阅读 0赞 转自:[https://blog.csdn.net/zkcharge/article/details/51727416][https_blog.csdn.net_zkcharge_article_details_51727416] static double pi = 3.14159265358979324; static double a = 6378245.0; static double ee = 0.00669342162296594323; public final static double x\_pi = 3.14159265358979324 \* 3000.0 / 180.0; public static double\[\] wgs2bd(double lat, double lon) \{ double\[\] wgs2gcj = wgs2gcj(lat, lon); double\[\] gcj2bd = gcj2bd(wgs2gcj\[0\], wgs2gcj\[1\]); return gcj2bd; \} public static double\[\] gcj2bd(double lat, double lon) \{ double x = lon, y = lat; double z = Math.sqrt(x \* x + y \* y) + 0.00002 \* Math.sin(y \* x\_pi); double theta = Math.atan2(y, x) + 0.000003 \* Math.cos(x \* x\_pi); double bd\_lon = z \* Math.cos(theta) + 0.0065; double bd\_lat = z \* Math.sin(theta) + 0.006; return new double\[\] \{ bd\_lat, bd\_lon \}; \} public static double\[\] bd2gcj(double lat, double lon) \{ double x = lon - 0.0065, y = lat - 0.006; double z = Math.sqrt(x \* x + y \* y) - 0.00002 \* Math.sin(y \* x\_pi); double theta = Math.atan2(y, x) - 0.000003 \* Math.cos(x \* x\_pi); double gg\_lon = z \* Math.cos(theta); double gg\_lat = z \* Math.sin(theta); return new double\[\] \{ gg\_lat, gg\_lon \}; \} public static double\[\] wgs2gcj(double lat, double lon) \{ double dLat = transformLat(lon - 105.0, lat - 35.0); double dLon = transformLon(lon - 105.0, lat - 35.0); double radLat = lat / 180.0 \* pi; double magic = Math.sin(radLat); magic = 1 - ee \* magic \* magic; double sqrtMagic = Math.sqrt(magic); dLat = (dLat \* 180.0) / ((a \* (1 - ee)) / (magic \* sqrtMagic) \* pi); dLon = (dLon \* 180.0) / (a / sqrtMagic \* Math.cos(radLat) \* pi); double mgLat = lat + dLat; double mgLon = lon + dLon; double\[\] loc = \{ mgLat, mgLon \}; return loc; \} private static double transformLat(double lat, double lon) \{ double ret = -100.0 + 2.0 \* lat + 3.0 \* lon + 0.2 \* lon \* lon + 0.1 \* lat \* lon + 0.2 \* Math.sqrt(Math.abs(lat)); ret += (20.0 \* Math.sin(6.0 \* lat \* pi) + 20.0 \* Math.sin(2.0 \* lat \* pi)) \* 2.0 / 3.0; ret += (20.0 \* Math.sin(lon \* pi) + 40.0 \* Math.sin(lon / 3.0 \* pi)) \* 2.0 / 3.0; ret += (160.0 \* Math.sin(lon / 12.0 \* pi) + 320 \* Math.sin(lon \* pi / 30.0)) \* 2.0 / 3.0; return ret; \} private static double transformLon(double lat, double lon) \{ double ret = 300.0 + lat + 2.0 \* lon + 0.1 \* lat \* lat + 0.1 \* lat \* lon + 0.1 \* Math.sqrt(Math.abs(lat)); ret += (20.0 \* Math.sin(6.0 \* lat \* pi) + 20.0 \* Math.sin(2.0 \* lat \* pi)) \* 2.0 / 3.0; ret += (20.0 \* Math.sin(lat \* pi) + 40.0 \* Math.sin(lat / 3.0 \* pi)) \* 2.0 / 3.0; ret += (150.0 \* Math.sin(lat / 12.0 \* pi) + 300.0 \* Math.sin(lat / 30.0 \* pi)) \* 2.0 / 3.0; return ret; \} 我提供的是JAVA代码,简单注释一下: pi: 圆周率。 a: 卫星椭球坐标投影到平面地图坐标系的投影因子。 ee: 椭球的偏心率。 x\_pi: 圆周率转换量。 transformLat(lat, lon): 转换方法,比较复杂,不必深究了。输入:横纵坐标,输出:转换后的横坐标。 transformLon(lat, lon): 转换方法,同样复杂,自行脑补吧。输入:横纵坐标,输出:转换后的纵坐标。 wgs2gcj(lat, lon): WGS坐标转换为GCJ坐标。 gcj2bd(lat, lon): GCJ坐标转换为百度坐标。 效果图: ![Center][] [https_blog.csdn.net_zkcharge_article_details_51727416]: https://blog.csdn.net/zkcharge/article/details/51727416 [Center]: /images/20220119/cb80b7047e1649a0ab665558342ce9ac.png
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