数据结构 - 反转单链表（C++）

旧城等待， 2022-04-22 05:08 281阅读 0赞

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// 反转单链表的循环算法（C++）#include <iostream>#define NULL 0using namespace std;struct Node{
          char data; Node* next;};Node* create(){ Node* head = NULL; Node* rear = head; Node* p; // The pointer points to new created node. char tmp; do {  cout << "Please input positive integer or #:";  cin >> tmp;  if(tmp != -1)  {   p = new Node;   p->data = tmp;   p->next = NULL;   if(head == NULL)   {    head = p;   }   else   {    rear->next = p;   }   rear = p;  } } while(tmp != '#'); return head;}void print(Node* head){ cout << "The current list is: "; Node* p = head; if(head != NULL) {  do  {   cout << p->data << cout << ' ';   p = p->next;  }  while(p != NULL); } cout << "\r\n";}void reverse(Node*& head) // Use & here since the function body changed the head pointer.{ if(head == NULL) {  return; } Node*pre, *cur, *ne; pre = head; cur = head->next; while(cur) {  ne = cur->next; // Store next pointer.  cur->next = pre; // Reverse the current code pointer.  pre = cur;  cur = ne; } head->next = NULL; head = pre;}int main(){ Node* list = create(); print(list); reverse(list); print(list); return 0;}// Output:/*Please input positive integer or #:1Please input positive integer or #:5Please input positive integer or #:8Please input positive integer or #:3Please input positive integer or #:2Please input positive integer or #:7Please input positive integer or #:9Please input positive integer or #:fPlease input positive integer or #:gPlease input positive integer or #:tPlease input positive integer or #:YPlease input positive integer or #:BPlease input positive integer or #:#The current list is: 10FC0C3E8 50FC0C3E8 80FC0C3E8 30FC0C3E8 20FC0C3E8 70FC0C3E8 90FC0C3E8 f0FC0C3E8 g0FC0C3E8 t0FC0C3E8 Y0FC0C3E8 B0FC0C3E8 #0FC0C3E8The current list is: #0FC0C3E8 B0FC0C3E8 Y0FC0C3E8 t0FC0C3E8 g0FC0C3E8 f0FC0C3E8 90FC0C3E8 70FC0C3E8 20FC0C3E8 30FC0C3E8 80FC0C3E8 50FC0C3E8 10FC0C3E8*/

// 反转单链表的递归算法（C++）#include <iostream>#define NULL 0using namespace std;struct Node{
          char  data; Node* next;};Node* create(){ Node* head = NULL; Node* rear = head; Node* p; // The pointer points to the new created node. char  tmp; do {  cout << "Please input integer or char '#':";  cin >> tmp;  if(tmp != '#')  {   p = new Node;   p->data = tmp;   p->next = NULL;   if(head == NULL)   {    head = p;   }   else   {    rear->next = p;   }   rear = p;  } } while(tmp != '#'); return head;}void print(Node* head){ cout << "The current list is: "; Node* p = head; if(head != NULL) {  do  {   cout << p->data << cout << ' ';   p = p->next;  }  while(p != NULL); } cout << "\r\n";}Node* reverseSingleLinkedListRecursive(Node* p, Node*& head){ if(p == NULL || p->next == NULL) {  head = p;  return p; } Node* tmp = reverseSingleLinkedListRecursive(p->next, head); tmp->next = p; p->next = NULL; // To prevent forming a ring. return p;}int main(){ Node* list = create(); print(list); reverseSingleLinkedListRecursive(list, list); print(list); return 0;}// Output:/*Please input integer or char '#':1Please input integer or char '#':2Please input integer or char '#':4Please input integer or char '#':6Please input integer or char '#':3Please input integer or char '#':8Please input integer or char '#':7Please input integer or char '#':9Please input integer or char '#':0Please input integer or char '#':#The current list is: 10F69C3E8 20F69C3E8 40F69C3E8 60F69C3E8 30F69C3E8 80F69C3E8 70F69C3E8 90F69C3E8 00F69C3E8The current list is: 00F69C3E8 90F69C3E8 70F69C3E8 80F69C3E8 30F69C3E8 60F69C3E8 40F69C3E8 20F69C3E8 10F69C3E8*/

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