web.xml基本配置

àì夳堔傛蜴生んèń 2022-04-18 01:28 138阅读 0赞

启动tomat正常，但是输入用户名和密码后进入不了index主页，报404错误，访问不到后台的方法，整理了一下思路，发现没配置web.xml

这可以说是一个低级错误了，下面关于web.xml的配置，可以正常访问后台方法了。登录成功

<!DOCTYPE web-app PUBLIC  
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"  
 "http://java.sun.com/dtd/web-app\_2\_3.dtd" >

<web-app>  
  <display-name>Archetype Created Web Application</display-name>  
  <filter>  
        <filter-name>characterEncodingFilter</filter-name>  
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>  
        <init-param>  
            <param-name>encoding</param-name>  
            <param-value>UTF-8</param-value>  
        </init-param>  
        <init-param>  
            <param-name>forceEncoding</param-name>  
            <param-value>true</param-value>  
        </init-param>  
    </filter>  
    <filter-mapping>  
        <filter-name>characterEncodingFilter</filter-name>  
        <url-pattern>/\*</url-pattern>  
    </filter-mapping>  
      
    <listener>  
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>  
    </listener>  
    <context-param>  
        <param-name>contextConfigLocation</param-name>  
        <param-value>classpath:spring-mybatis.xml</param-value>  
    </context-param>  
      
    <servlet>  
        <servlet-name>DispatcherServlet</servlet-name>  
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
        <init-param>  
            <param-name>contextConfigLocation</param-name>  
            <param-value>classpath:spring-mvc.xml</param-value>  
        </init-param>  
        <load-on-startup>1</load-on-startup>  
    </servlet>  
    <servlet-mapping>  
        <servlet-name>DispatcherServlet</servlet-name>  
        <url-pattern>/</url-pattern>  
    </servlet-mapping>  
    <error-page>  
        <error-code>404</error-code>  
        <location>/404.jsp</location>  
    </error-page>  
</web-app>