List is a raw type. References to generic type List<E> should be parameterized

痛定思痛。 2022-04-04 02:51 183阅读 0赞

编译环境：Eclipse

问题：编译集合类型List、Set、Map代码时，编译器出现下面的警告：

List is a raw type. References to generic type List<E> should be parameterized
    Set is a raw type. References to generic type Set<E> should be parameterized
    Map is a raw type. References to generic type Map<K,V> should be parameterized

具体的问题代码：

List addressList;
    
    public void setAddressList(List addressList) {
        this.addressList=addressList;
    }
    public List getAddressList() {
        System.out.println("List Elements :" + addressList);
        return addressList;
    }

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警告的内容是，需要我们给出数据的原始类型，具体的修改方法如下：

List<String> addressList;
    
    public void setAddressList(List<String> addressList) {
        this.addressList=addressList;
    }
    public List<String> getAddressList() {
        System.out.println("List Elements :" + addressList);
        return addressList;
    }

问题下成功解决。

Set集合类型跟List集合类型一样，具体说一下Map集合类型。

Map、HashMap集合类型问题总结：(因为这两种集合类型都需要指出具体的key值和value值)

问题：
    Map.Entry is a raw type. References to generic type Map<K,V>.Entry<K,V> should be parameterized

解决方法：
    HashMap<Object, Object> addressHash;
    HashMap<String, Long> addressHash;
    Map<String, Long> addressMap;

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