Revit API判断直线相交关系移动风管

小鱼儿 2022-03-31 05:18 261阅读 0赞

start

// 风管对齐   
\[TransactionAttribute(Autodesk.Revit.Attributes.TransactionMode.Manual)\]  
public class cmdDuctAlign : IExternalCommand  
\{  
private XYZ GetIntersection(Line line1, Line line2)  
\{  
IntersectionResultArray results;  
  
SetComparisonResult result  
= line1.Intersect(line2, out results);  
// SetComparisonResult.Subset  
 // SetComparisonResult.Superset    
 if (SetComparisonResult.Overlap == result) // 没有交点，可能是平行，也可以是延长线相交。   
 throw new InvalidOperationException(  
" Overlap ");  
if (SetComparisonResult.Disjoint == result) // 不相交   
 throw new InvalidOperationException(  
" Disjoint ");  
if (SetComparisonResult.Superset == result) // 包含，子集   
 throw new InvalidOperationException(  
" Superset ");  
if (SetComparisonResult.Subset == result) // 交集   
 throw new InvalidOperationException(  
" Subset ");  
if (results == null || results.Size != 1)  
throw new InvalidOperationException(  
" Could not extract line intersection point. ");  
  
IntersectionResult iResult  
= results.get\_Item( 0);  
  
return iResult.XYZPoint;  
\}  
public Result Execute(ExternalCommandData commandData, ref string messages, ElementSet elements)  
\{  
UIApplication app = commandData.Application;  
Document doc = app.ActiveUIDocument.Document;  
Selection sel = app.ActiveUIDocument.Selection;  
  
SplitButtonData splitButtonData = new SplitButtonData( "", "");  
PushButton pbtn = new PushButton();  
RibbonPanel rpanel = new RibbonPanel();  
  
  
Transaction ts = new Transaction(doc, " revit ");  
ts.Start();  
  
IList<Reference> refDucts = sel.PickObjects(ObjectType.Element, " duct ");  
Duct duct1 = doc.GetElement(refDucts.ElementAt( 0)) as Duct;  
Duct duct2 = doc.GetElement(refDucts.ElementAt( 1)) as Duct;  
LocationCurve lCurve1 = duct1.Location as LocationCurve;  
LocationCurve lCurve2 = duct1.Location as LocationCurve;  
XYZ xyz11 = lCurve1.Curve.get\_EndPoint( 0);  
XYZ xyz12 = lCurve1.Curve.get\_EndPoint( 1);  
XYZ xyz21 = lCurve2.Curve.get\_EndPoint( 0);  
XYZ xyz22 = lCurve2.Curve.get\_EndPoint( 1);  
// 判断线段相交关系   
 Line line1 = Line.get\_Bound(xyz11, xyz12);  
Line line2 = Line.get\_Bound(xyz21, xyz22);  
GetIntersection(line1, line2);  
  
\#region 风管移动  
  
// 转化到平面   
 XYZ xyz1 = new XYZ(xyz11.X, xyz11.Y, 0);  
XYZ xyz2 = new XYZ(xyz12.X, xyz12.Y, 0);  
XYZ xyz3 = new XYZ(xyz21.X, xyz21.Y, 0);  
XYZ xyz4 = new XYZ(xyz22.X, xyz22.Y, 0);  
// 找到与直线垂直的向量   
 XYZ vec1 = xyz2 - xyz1;  
XYZ zVec = new XYZ( 0, 0, 1);  
XYZ nVec = vec1.CrossProduct(zVec).Normalize(); // 两条线相交的面对应的向量   
 TaskDialog.Show( " vec ", nVec.CrossProduct(zVec).Normalize().ToString());  
lCurve2.Move(nVec);  
  
\#endregion  
  
ts.Commit();  
  
return Result.Succeeded;  
\}  
\}

url: [http://greatverve.cnblogs.com/p/revit-api-line-SetComparisonResult.html][http_greatverve.cnblogs.com_p_revit-api-line-SetComparisonResult.html]

参考：

http://revit.haotui.com/thread-171-1-32.html

http://revit.haotui.com/thread-489-1-23.html

[http_greatverve.cnblogs.com_p_revit-api-line-SetComparisonResult.html]: http://greatverve.cnblogs.com/p/revit-api-line-SetComparisonResult.html