12554 - A Special "Happy Birthday" Song!!!

亦凉 2022-03-31 02:27 96阅读 0赞

# Problem A #

## A Special "\[H\]appy Birthday" Song!!! ##

There are *n* people (excluding myself) in my 30th birthday party. They sing the traditional "happy birthday" song:

> Happy birthday to you! Happy birthday to you! Happy birthday to Rujia! Happy birthday to you!!!

Since I love music, I want to hear something more interesting, not that everyone sings together. Ah yes, I want one person to sing one word!

For example, there are three people: Mom, Dad, Girlfriend, I'd like them to sing like this:

Mom: Happy
    Dad: birthday
    Girlfriend: to
    Mom: you
    Dad: Happy
    Girlfriend: birthday
    Mom: to
    Dad: you
    Girlfriend: Happy
    Mom: birthday
    Dad: to
    Girlfriend: Rujia
    Mom: Happy
    Dad: birthday
    Girlfriend: to
    Mom: you

Very nice, right? What if there are more than 16 people? That's easy: repeat the song until everyone has sung at least once :)

Please, don't stop in the middle of the song.

## Input ##

There is only one test case. The first line contains a single integer *n* (1<=*n*<=100). Then each of the next n lines contains a capitalized name (i.e. one upper-case letter followed by zero or more lower-case letters). Each name contains at most 100 characters and do not have whitespace characters inside.

## Output ##

Output the song, formatted as above.

## Sample Input ##

3
    Mom
    Dad
    Girlfriend

## Output for the Sample Input ##

#include<stdio.h>
    #include<math.h>
    int main()
    {
    	int n,p,i,j,k;
    	char s[100][100];
    	char c[16][100]={"Happy","birthday","to","you","Happy","birthday","to","you","Happy","birthday","to","Rujia","Happy","birthday","to","you"};
    	while(scanf("%d",&n))
    	{
    		for(i=0;i<n;i++)
    			scanf("%s",s[i]);
    		if(n>16)
    			p=ceil(n/16)+1;
    		for(i=0,j=0,k=0;j<16*p;i++,j++,k++)
    		{
    			if(i==n) i=0;
    			if(j==16) k=0;
    			printf("%s: %s\n",s[i],c[k]);
    		}
    	}
    	return 0;
    }