报错：java.io.FileNotFoundException: class path resource ..cannot be opened because it does not exist

阳光穿透心脏的1/2处 2022-03-30 10:43 201阅读 0赞

# 配置spring是出现的问题： #

# java.io.FileNotFoundException: class path resource ..cannot be opened because it does not exist  #

--------------------

初学Spring在用Resource rs=new ClassPathResource("applicationContext.xml");时老是遇到这个错误。后来发现用  
ApplicationContext ctx=new FileSystemXmlApplicationContext("WebContent/[WEB-INF][]/applicationContext.xml")；可以解决这个问题。

仔细研究了下：  
之所以我用ClassPathResource中找不到applicationContext.xml是因为我的这个[xml文件][xml]在建工程的时候默认放在了WebContent/[WEB-INF][]/下面，但是用ClassPathResource是在[当前目录][Link 1]也就是我这个java文件所在的目下进行寻找。因此把这个[xml文件][xml]移动到我的src目录下面就ok了。  
同理如果是用ApplicationContext ctx=new ClassPathXmlApplicationContext()也是这样是从当前路径寻找，[xml文件][xml]应在[当前目录][Link 1]下。  
但是如果用FileSystemXmlApplicationContext呢，它是根据指定的路径来进行寻找，所以要把路径写完整。现在xml路径在src文件夹下。那就要写：ApplicationContext ctx=new FileSystemXmlApplicationContext("src/applicationContext.xml");

这是比较直接简单的写法，后来又查了查发现对于FileSystemXmlApplicationContext也可以采用：  
1.**加上classpath:前缀（这个时候xml要放在[当前目录][Link 1]也就是src下）**  
ApplicationContext ctx=new FileSystemXmlApplicationContext("classpath:applicationContext.xml");  
2.**加上file:把路径写全(用这个方法xml可以放任意地方)**  
ApplicationContext ctx=new ClassPathXmlApplicationContext("ApplicationContext ctx=new ClassPathXmlApplicationContext("file:F:/workspace/SpringExercis/src/applicationContext.xml");  
综上，最简单的方法还是老老实实把xml放在src下方便。

[WEB-INF]: https://www.baidu.com/s?wd=WEB-INF&tn=SE_PcZhidaonwhc_ngpagmjz&rsv_dl=gh_pc_zhidao
[xml]: https://www.baidu.com/s?wd=xml%E6%96%87%E4%BB%B6&tn=SE_PcZhidaonwhc_ngpagmjz&rsv_dl=gh_pc_zhidao
[Link 1]: https://www.baidu.com/s?wd=%E5%BD%93%E5%89%8D%E7%9B%AE%E5%BD%95&tn=SE_PcZhidaonwhc_ngpagmjz&rsv_dl=gh_pc_zhidao

报错：java.io.FileNotFoundException: class path resource ..cannot be opened because it does not exist

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