List对象数组排序（根据指定的属性）

Myth丶恋晨 2022-03-16 04:06 355阅读 0赞

话不多说直接上代码

/**
     * @author 633805 LYH
     * @version V1.0
     * @description 对类的描述
     * @create 2019-02-26 14:23
     * @since 1.7
     */
    public class User {
    
        private Long uid;
    
        private String name;
    
        private Integer age;
    
        public User(Long uid, String name, Integer age) {
            this.uid = uid;
            this.name = name;
            this.age = age;
        }
    
        public Long getUid() {
            return uid;
        }
    
        public void setUid(Long uid) {
            this.uid = uid;
        }
    
        public String getName() {
            return name;
        }
    
        public void setName(String name) {
            name = name;
        }
    
        public Integer getAge() {
            return age;
        }
    
        public void setAge(Integer age) {
            this.age = age;
        }
    
        @Override
        public String toString() {
            return "User{" +
                    "uid=" + uid +
                    ", Name='" + name + '\'' +
                    ", age=" + age +
                    '}';
        }
    }

import java.util.ArrayList;
    import java.util.Collections;
    import java.util.Comparator;
    import java.util.List;
    import java.util.stream.Collectors;
    
    /**
     * @author 633805 LYH
     * @version V1.0
     * @description 对类的描述
     * @create 2019-02-21 11:49
     * @since 1.7
     */
    public class C {
        public static void main(String[] args) {
    
            //构造user对象
            User user1 = new User(1L, "lyh",21);
    
            User user2 = new User(2L, "abc",18);
    
            List<User> list = new ArrayList<User>();
    
            list.add(user1);
            list.add(user2);
    
            list.forEach(System.out::println);
    
            //方法一 根据年龄进行排序
    
           List<User> sortList =  list.stream().sorted(Comparator.comparing(User::getAge)).collect(Collectors.toList());
            //打印
            sortList.forEach(System.out::println);
    
            //方法二  根据年龄进行排序
            Collections.sort(list, (Comparator) (o1, o2) -> {
                User u1 = (User) o1;
                User u2 = (User) o2;
                return u1.getAge().compareTo(u2.getAge());
            });
    
            //打印
            list.forEach(System.out::println);
    
        }
    }