Python字典Update()函数及一次bug解决

柔光的暖阳◎ 2022-02-26 02:42 371阅读 0赞

一、用法  
python字典中的update方法可用于字典的键值对更新、添加。示例：

dic = {"zhangsan": 89}
    dic.update({"lisi":88})
    dic
    {'zhangsan': 89, 'lisi': 88}

二、bug描述  
在构造数据的时候，如下更新字典bank\_code，定义在for循环以外时，会导致所有的banl\_code都是PSBC：

test_data = {
                "top": "2",
                 "busId": "XXXX",
                 "features":
                     {
                         "applist": "(38)嘻哈龟牛皮兔,10-10 极端令人惊异的网格块益智世界游戏"
                     },
                "multiFeatures": {}
    }
    s = 'ICBC CNCB PSBC'
    dic = {"tag20": 0, "tag21": 0, "tag22": 1, "tag23": 1, "tag24": 0, "tag25": 1, "tag26": 0, "tag27": 0, "tag17": 0,
           "bank_code": "BCOM", "tag30": 0, "tag8": 0, "tag31": 1, "tag10": 0, "tag32": 0, "tag9": 0,
           }
    for i in s.split(' '):
        dic['bank_code'] = i
        new_d = {}
        new_d[str(i)] = dic
        test_data['multiFeatures'].update(new_d)
    print(test_data)

![在这里插入图片描述][20190328193550579.png]  
三、解决方法  
将dic 定义在for循环以内，完美解决，不会导致所有的bank\_code都是PSBC：

test_data = {
                "top": "2",
                 "busId": "XXXX",
                 "features":
                     {
                         "applist": "(38)嘻哈龟牛皮兔,10-10 极端令人惊异的网格块益智世界游戏"
                     },
                "multiFeatures": {}
    }
    s = 'ICBC CNCB PSBC'
    for i in s.split(' '):
        dic = {"tag20": 0, "tag21": 0, "tag22": 1, "tag23": 1, "tag24": 0, "tag25": 1, "tag26": 0, "tag27": 0, "tag17": 0,
               "bank_code": "BCOM", "tag30": 0, "tag8": 0, "tag31": 1, "tag10": 0, "tag32": 0, "tag9": 0,
               }
        dic['bank_code'] = i
        new_d = {}
        new_d[str(i)] = dic
        test_data['multiFeatures'].update(new_d)
    print(test_data)

![在这里插入图片描述][20190328193626510.png]

[20190328193550579.png]: /images/20220226/fe41c45d13874079bd5d91b51854c7ec.png
[20190328193626510.png]: /images/20220226/beee2c0e490b4032bd02fb1cc25edb75.png