PAT A 1025 PAT Ranking

怼烎@ 2022-02-01 10:53 160阅读 0赞

#                            1025 PAT Ranking (25 分) #

Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged immediately after the test. Now it is your job to write a program to correctly merge all the ranklists and generate the final rank.

### Input Specification: ###

Each input file contains one test case. For each case, the first line contains a positive number N (≤100), the number of test locations. Then N ranklists follow, each starts with a line containing a positive integer K (≤300), the number of testees, and then K lines containing the registration number (a 13-digit number) and the total score of each testee. All the numbers in a line are separated by a space.

### Output Specification: ###

For each test case, first print in one line the total number of testees. Then print the final ranklist in the following format:

> registration\_number final\_rank location\_number local\_rank

The locations are numbered from 1 to N. The output must be sorted in nondecreasing order of the final ranks. The testees with the same score must have the same rank, and the output must be sorted in nondecreasing order of their registration numbers.

### Sample Input: ###

> 2  
> 5  
> 1234567890001 95  
> 1234567890005 100  
> 1234567890003 95  
> 1234567890002 77  
> 1234567890004 85  
> 4  
> 1234567890013 65  
> 1234567890011 25  
> 1234567890014 100  
> 1234567890012 85  
>

### Sample Output: ###

> 9  
> 1234567890005 1 1 1  
> 1234567890014 1 2 1  
> 1234567890001 3 1 2  
> 1234567890003 3 1 2  
> 1234567890004 5 1 4  
> 1234567890012 5 2 2  
> 1234567890002 7 1 5  
> 1234567890013 8 2 3  
> 1234567890011 9 2 4

思路：

用结构体存放每个学生的多项信息（准考证号、分数、考场号以及考场内排名），且排名需要用到排序函数，规则为：

（1）当分数不同时，从高到低排序

（2）分数相同，按准考证号从小到大排序

计划将程序分为三大模块：

模块1：按考场读入各考场的信息，并对当前读入考场的所有考生进行排序，后将该考场所有考生的排名写入他们的结构体中

模块2：对所有考生进行排序

模块3：按顺序一边计算总排名，一边输出所有考生的信息

#include<stdio.h>
    #include<string.h>
    #include<algorithm>
    using namespace std;
    struct student{
        char id[15];
        int score;
        int location_number;
        int location_rank;
    }stu[30010];
    bool cmp(Student a,Student b)
    {
        if(a.score!=b.score)
           return a.score>b.score;
        else
           return strcmp(a.id,b.id)<0;
    }
    int main()
    {
        int n,k,num=0;
        scanf("%d",&n);
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&k);
            for(int j=0;j<k;j++)
            {
                scanf("%s %d",stu[num].id,&stu[num].score);
                stu[num].location_number=i;
                num++;
            }
            sort(stu+num-k,stu+num,cmp);
            stu[num-k].location_rank=1;
            for(int j=num-k+1;j<num;j++)
            {
                if(stu[j].score==stu[j-1].score)
                {
                    stu[j].local_rank=stu[j-1].local_rank;
                }
                else
                {
                    stu[j].local_rank=j+1-(num-k);
                }
            }
        }
        printf("%d\n",num);
        sort(stu,stu+num,cmp);
        int r=1;
        for(int i=0;i<num;i++)
        {
            if(i>0&&stu[i].score!=stu[i-1].score)
            {
                r=i+1;
            }
            printf("%s",stu[i].id);
            printf("%d %d %d\n",r,stu[i].location_number,stu[i].local_rank)
            
        }
        return 0;
    }