数组a，b ：数组b是数组a的子集，去掉数组b中不符合该条件的元素

男娘i 2022-02-01 10:17 217阅读 0赞

案例一：列表

a=[1,2,3,4,5,6]
    b=[3,5,0]
    print(a,b)
    flag=[]
    for i in range(0,len(b)):
         flag.append(0)
         for j in a:
             if b[i]==j:
                  flag[i]=1
                  break 
    print(flag)
    for i in range(0,len(b)):
        if flag[i]==0:
             b.remove(b[i])
    print(b)

输出：

(\[1, 2, 3, 4, 5, 6\], \[3, 5, 0\])  
\[1, 1, 0\]  
\[3, 5\]

案例2：字典

G={"A":{"B","D"},
        "B":{"C","E"},
        "C":{"E","F"},
        "D":{"G"},
        "E":{"D","F","G","H","M"},
        "F":{"H"},
        "G":{"H"},
        "H":{}}
    
    def com(a,b):
        flag=[]
       
        print("b:",type(b),b)
    
        for i in range(0,len(b)):
           # print("b[i]:",b[i])
            flag.append(0)
            #print("b[i]:",b[i])
            for j in range(0,len(a)):
                if b[i]==a[j]:
                    flag[i]=1
                    #print("success")
                    break 
    
        #print("flag:",flag)
        for i in range(0,len(b)):
            if flag[i]==0:
                print("error")
                b.remove(b[i])
        print("b",b)       
        return b
    
    
    a=[]
    b=[]
    c=[]
    for i,j in  G.items():
          a.append(i)  
    print("a:",a)
    for i,j in G.items():
        if i=="E":
          b.append(j)
          for n in b:
               data=n
          for y in data: 
             c.append(y)
          print("c:",c)
          c=com(a,c)
          print("c:",c,type(c),"i",i)
          G[i]=c
          b.pop(0)
    print(G)

输出：

G=\{"A":\{"B","D"\},

"B":\{"C","E"\},

"C":\{"E","F"\},

"D":\{"G"\},

"E":\{"D","F","G","H"\},

"F":\{"H"\},

"G":\{"H"\},

"H":\{\}\}