Promise实现sleep功能 比眉伴天荒 2022-01-28 07:07 235阅读 0赞 async function test() { for (var i = 0; i < 10; i++) { await sleep(1000); console.log(i); } } function sleep(delay) { return new Promise((resolve, reject) => { setTimeout(() => { try { resolve(1) } catch (e) { reject(0) } }, delay); }) }
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