note 集合转树形结构

￡神魔★判官ぃ 2022-01-14 10:43 171阅读 0赞

package com.ctl;
 
 import com.hanshow.wise.base.common.util.StringUtil;
 import net.sf.json.JSONArray;
 import org.springframework.beans.BeanUtils;
 
 import java.util.ArrayList;
 import java.util.Deque;
 import java.util.List;
 import java.util.concurrent.ConcurrentLinkedDeque;
 
 /**
 * Title: T
 * Description: 
 * Copyright: Copyright (c) 2018
 * Company: www.hanshow.com
 * note 集合转数
 * @author guolin
 * @version 1.0
 * @date 2019-05-31 15:22
 */
 
 public class Node {
 private Integer id;
 private Integer pid;
 private Integer seq;
 private List<Node> children;
 
 public Node() {
 }
 
 public Node(Integer id, Integer pid, Integer seq) {
 this.id = id;
 this.pid = pid;
 this.seq = seq;
 }
 
 public Node(Integer id, Integer pid, Integer seq, List<Node> children) {
 this.id = id;
 this.pid = pid;
 this.seq = seq;
 this.children = children;
 }
 
 public Integer getId() {
 return id;
 }
 
 public void setId(Integer id) {
 this.id = id;
 }
 
 public Integer getPid() {
 return pid;
 }
 
 public void setPid(Integer pid) {
 this.pid = pid;
 }
 
 public Integer getSeq() {
 return seq;
 }
 
 public void setSeq(Integer seq) {
 this.seq = seq;
 }
 
 public List<Node> getChildren() {
 return children;
 }
 
 public void setChildren(List<Node> children) {
 this.children = children;
 }
 
 
 public static void main(String[] args) {
 //保证allNode时有序的 根据pid和seq排序后的
 List<Node> allNode = new ArrayList<>();
 Node node1 = new Node(1001, null, 1);
 Node node2 = new Node(1002, null, 2);
 Node node3 = new Node(1003, null, 3);
 
 Node node1_001 = new Node(1001001, 1001, 1);
 Node node1_002 = new Node(1001002, 1001, 2);
 Node node1_003 = new Node(1001003, 1001, 3);
 
 Node node2_001 = new Node(1002001, 1002, 1);
 Node node2_002 = new Node(1002002, 1002, 2);
 
 Node node3_001 = new Node(1003001, 1003, 1);
 
 allNode.add(node1);
 allNode.add(node2);
 allNode.add(node3);
 
 allNode.add(node1_001);
 allNode.add(node1_002);
 allNode.add(node1_003);
 
 allNode.add(node2_001);
 allNode.add(node2_002);
 
 allNode.add(node3_001);
 
 
 List<Node> rootResourceList = new ArrayList<>();
 Deque<Node> deque = new ConcurrentLinkedDeque<>();
 
 if (allNode != null && allNode.size() > 0) {
 allNode.stream().forEach(resource -> {
 deque.add(resource);
 });
 }
 
 int size = allNode.size();
 for (int i = 0; i < size; i++) {
 Node node = deque.peek();
 if (node.getPid() == null || 0 == node.getPid()) {
 rootResourceList.add(node);
 deque.poll();
 } else {
 break;
 }
 
 }
 addResourceChild(rootResourceList, deque);
 System.out.println(StringUtil.formatJson(JSONArray.fromObject(rootResourceList).toString()));
 }
 
 /**
 * list 转 tree
 *
 * @param resourceList
 * @param deque
 */
 private static synchronized void addResourceChild(List<Node> resourceList, Deque<Node> deque) {
 if (deque == null || resourceList == null || resourceList.size() == 0) {
 return;
 }
 try {
 int size = resourceList.size();
 for (int i = 0; i < size; i++) {
 Node node = resourceList.get(i);
 List<Node> children = new ArrayList<>();
 node.setChildren(children);
 
 Node poll = deque.poll();
 if (poll != null) {
 Node pollRoot = new Node();
 BeanUtils.copyProperties(poll, pollRoot);
 int times = 1;
 while (poll != null) {
 if (poll.getId().intValue() == pollRoot.getId().intValue() && times > 1) {
 deque.addFirst(poll);
 break;
 }
 if (poll.getPid() != null && poll.getPid().intValue() == node.getId().intValue()) {
 children.add(poll);
 }
 Node pollT = new Node();
 BeanUtils.copyProperties(poll, pollT);
 deque.add(pollT);
 poll = deque.poll();
 times++;
 }
 }
 addResourceChild(children, deque);
 }
 } catch (Exception e) {
 
 }
 }
 
 }