java中mongdb的objectid序列化问题（返回json格式而不是字符串问题）

朱雀 2021-12-17 11:35 433阅读 0赞

1.解决方式：

1.1Response统一返回控制

import org.bson.types.ObjectId;
    import org.springframework.core.MethodParameter;
    import org.springframework.http.MediaType;
    import org.springframework.http.converter.HttpMessageConverter;
    import org.springframework.http.server.ServerHttpRequest;
    import org.springframework.http.server.ServerHttpResponse;
    import org.springframework.web.bind.annotation.ControllerAdvice;
    import org.springframework.web.servlet.mvc.method.annotation.ResponseBodyAdvice;
    
    import com.alibaba.fastjson.JSON;
    import com.alibaba.fastjson.JSONObject;
    import com.alibaba.fastjson.serializer.SerializeConfig;
    /**
     * 统一返回response控制
     * @author cf
     *
     */
    @ControllerAdvice
    public class MyResponseBodyAdvice implements ResponseBodyAdvice<Object>{
    
    	 @Override
    	    public boolean supports(MethodParameter returnType, Class<? extends HttpMessageConverter<?>> converterType) {
    	        return true;
    	    }
    
    	    @Override
    	    public Object beforeBodyWrite(Object body, MethodParameter returnType, MediaType selectedContentType,
    	            Class<? extends HttpMessageConverter<?>> selectedConverterType, ServerHttpRequest request,
    	            ServerHttpResponse response) {
    
    	        SerializeConfig config = new SerializeConfig();
    	        //解决mongdb id序列化问题
    	        config.put(ObjectId.class, new ObjectIdJsonSerializer());
    	        return JSONObject.parse(JSON.toJSONString(body, config));
    	    }
    	
    
    }

1.2序列化时进行转换

package com.qjxs.advice;
    
    import java.io.IOException;
    
    import org.bson.types.ObjectId;
    
    import com.alibaba.fastjson.serializer.JSONSerializer;
    import com.alibaba.fastjson.serializer.ObjectSerializer;
    import com.alibaba.fastjson.serializer.SerializeWriter;
    import java.lang.reflect.Type;
    /**
     * mongdb Object序列化问题
     * @author cf
     *
     */
    public class ObjectIdJsonSerializer implements ObjectSerializer{
    
    	
    	 @Override
    	    public void write(JSONSerializer serializer, Object object, Object fieldName, Type fieldType,int features) throws IOException {
    	        SerializeWriter out = serializer.getWriter();
    	        if (object == null) {
    	            serializer.getWriter().writeNull();
    	            return;
    	        }
    	        out.write("\"" + ((ObjectId) object).toString() + "\"");
    	    }
    }