AngularJS实现ajax请求的方法

小灰灰 2021-12-17 00:27 246阅读 0赞

【HTML 代码】

1 <!DOCTYPE html>
     2 <html>
     3 <head>
     4   <meta charset="utf-8">
     5   <meta name="viewport" content="width=device-width,user-scalable=no, initial-scale=1">
     6   <link rel="stylesheet" type="text/css" href="" />
     7   <title>angularjs实现 ajax</title>
     8 </head>
     9 <body ng-app="HelloAjax">
    10   <div ng-controller="HelloAjax">
    11     <form>
    12       <input type="text" ng-model="username" />
    13       <input type="text" ng-model="email" />
    14     </form>
    15     <table>
    16      <tr ng-repeat="user in users">
    17        <td>{
        {user.username}}</td>
    18        <td>{
        {user.email}}</td>
    19      </tr>
    20     </table>
    21     <button ng-click="get_more();">get more</button>
    22   </div>
    23 </body>
    24 <script type="text/javascript" src="./js/angular.min.js" charset="utf-8"></script>
    25   <script type="text/javascript" src="ajax.js" charset="utf-8"></script>
    26 </html>

【js代码 ajax.js】

1 var myModule = angular.module("HelloAjax",[]);
     2 myModule.controller("HelloAjax",["$scope","$http",function HelloAjax($scope,$http){
     3   /*
     4   $scope.users=[{'username':"zhangsan","email":"zs@11.com"},
     5     {'username':"zhangsan2","email":"zs@22.com"},
     6     {'username':"zhangsan3","email":"zs@33.com"}];
     7   */
     8   $scope.get_more = function(){
     9     $http({
    10         method: "POST",
    11         url: "./ajax.php",
    12         data:{'username':$scope.username,
    13            'email':$scope.email
    14           }
    15       }).
    16       success(function(data, status) {
    17        //$scope.status = status;
    18         $scope.users = data;
    19       }).
    20       error(function(data, status) {
    21        //$scope.data = data || "Request failed";
    22        //$scope.status = status;
    23      });
    24    }
    25 }]);

【PHP代码 ajax.php】

1 <?php
     2 //获取参数
     3 $data = file_get_contents("php://input");
     4 $user = json_decode($data);
     5 //查询数据库
     6 $conn = mysql_connect("localhost","root","");
     7 mysql_select_db("test");
     8 $sql ="select username,email from users ";
     9 $res = mysql_query($sql,$conn);
    10 $users = array();
    11 while($row = mysql_fetch_assoc($res)){
    12   $users[] = $row;
    13 }
    14 //当然这里简化了插入数据库
    15 $users[] = array('username'=>$user->username,
    16          'email'=>$user->email);
    17 //返回数据库
    18 echo json_encode($users);

原文地址：http://www.jb51.net/article/97924.htm

转载于:https://www.cnblogs.com/lili-lili-lili-lili/p/6206509.html