Java多线程消费者和生产者模式并发死锁问题解决

╰+攻爆jí腚メ 2021-12-12 06:04 218阅读 0赞

以下是文章的主要核心点

1.  文中采用Stream流的方式创建多个生产者和消费者
2.  利用对象的wait()进行阻塞
3.  利用synchronized 的原理
4.  创建唯一的Monitor的LOCK对象
5.  通过notifyAll()唤醒阻塞，此处不能用notify()

import java.util.stream.Stream;
    
    public class ProduceConsumer { 
        private int i;
        final private Object LOCK = new Object();
        private volatile boolean isProduced = false;
    
        public void produce() throws InterruptedException { 
            synchronized (LOCK) { 
                if (isProduced) { 
                    LOCK.wait();
                } else { 
                    i++;
                    System.out.println(Thread.currentThread().getName()+" P-----> " + i);
                    isProduced = true;
                    LOCK.notifyAll();
                }
            }
        }
    
        public void consumer() throws InterruptedException { 
            synchronized (LOCK) { 
                if (isProduced) { 
                    System.out.println(Thread.currentThread().getName()+" C-----> " + i);
                    isProduced = false;
                    LOCK.notifyAll();
                } else { 
                    LOCK.wait();
                }
            }
        }
    
        public static void main(String[] args) { 
            ProduceConsumer produceConsumer = new ProduceConsumer();
            Stream.of("P1", "P2", "p3").forEach(name -> { 
                new Thread(() -> { 
                    while (true) { 
                        try { 
                            produceConsumer.produce();
                        } catch (InterruptedException e) { 
                            e.printStackTrace();
                        }
                    }
                },name).start();
            });
            Stream.of("C1", "C2", "C3").forEach(name -> { 
                new Thread(() -> { 
                    while (true) { 
                        try { 
                            produceConsumer.consumer();
                        } catch (InterruptedException e) { 
                            e.printStackTrace();
                        }
                    }
                },name).start();
            });
            
        }
    }