Java substring 遇到的坑
如下:定义一个string【长度为6,那么下标就应该是0到5】:
String s = "123456";
我们如何取出整个s呢?
当初我的想法是s.substring(0,5);======>>>>试验一下
这时有点懵,点击去查看源码发现确实是理解错误了,他并不包含最后一个【根据源码的例子可以看出】
sbustring源码:
/**
* Returns a new string that is a substring of this string. The
* substring begins at the specified <code>beginIndex</code> and
* extends to the character at index <code>endIndex - 1</code>.
* Thus the length of the substring is <code>endIndex-beginIndex</code>.
* <p>
* Examples:
* <blockquote><pre>
* "hamburger".substring(4, 8) returns "urge"
* "smiles".substring(1, 5) returns "mile"
* </pre></blockquote>
*
* @param beginIndex the beginning index, inclusive.
* @param endIndex the ending index, exclusive.
* @return the specified substring.
* @exception IndexOutOfBoundsException if the
* <code>beginIndex</code> is negative, or
* <code>endIndex</code> is larger than the length of
* this <code>String</code> object, or
* <code>beginIndex</code> is larger than
* <code>endIndex</code>.
*/
public String substring(int beginIndex, int endIndex) {
if (beginIndex < 0) {
throw new StringIndexOutOfBoundsException(beginIndex);
}
if (endIndex > value.length) {
throw new StringIndexOutOfBoundsException(endIndex);
}
int subLen = endIndex - beginIndex;
if (subLen < 0) {
throw new StringIndexOutOfBoundsException(subLen);
}
return ((beginIndex == 0) && (endIndex == value.length)) ? this
: new String(value, beginIndex, subLen);
}
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