javax.servlet.ServletException: [Ljava.lang.Object;

红太狼 2021-08-11 06:32 216阅读 0赞

# HTTP Status 500 - #

--------------------

**type** Exception report

**message**

**description** The server encountered an internal error () that prevented it from fulfilling this request.

**exception**

javax.servlet.ServletException: [Ljava.lang.Object;
    	org.apache.struts.action.RequestProcessor.processException(RequestProcessor.java:523)
    	org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:421)
    	org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:224)
    	org.apache.struts.action.ActionServlet.process(ActionServlet.java:1194)
    	org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:432)
    	javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
    	javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
    	com.zq.utils.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:24)

**root cause**

java.lang.ClassCastException: [Ljava.lang.Object;
    	com.zq.struts.user.action.UserAction.userLogin(UserAction.java:403)
    	com.zq.struts.user.action.UserAction.doExecute(UserAction.java:118)
    	com.zq.struts.action.BaseAction.execute(BaseAction.java:98)
    	org.springframework.web.struts.DelegatingActionProxy.execute(DelegatingActionProxy.java:106)
    	org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:419)
    	org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:224)
    	org.apache.struts.action.ActionServlet.process(ActionServlet.java:1194)
    	org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:432)
    	javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
    	javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
    	com.zq.utils.SetCharacterEncodingFilter.doFilter(SetCharacterEncodingFilter.java:24)

**note** The full stack trace of the root cause is available in the Apache Tomcat/5.0.28 logs.

--------------------

一下内容摘自互联网（转）

String sql = "select \{P.\*\} from Personreg P where P.name = :name and P.password = :password";  
以上Query的list()方法返回的集合中存放的是对象数组的元素，这个对象数组中才是存放了Personreg对象。  
应该if (iterator.hasNext())\{  
                Object\[\] row = (Object\[\])iterator.next();  
                Personreg personreg = (Personreg)row\[0\];  
                System.out.println(personreg.getId());  
        \}

另外String hql = "from Personreg P where P.name = :name and P.password = :password"，这里，因为你语句中用了别名.属性名，所以前面一定要指定别名，否则语法错误; 或者不指定别名的前况下直接指定属性名就好，可以用String hql = "from Personreg where name = :name and password = :password"。

javax.servlet.ServletException: [Ljava.lang.Object;

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