实现浮点数转换成人民币读法字符串（Java）-蒲公英云

实现浮点数转换成人民币读法字符串（Java）

末蓝、 2021-06-24 13:59 452阅读 0赞

public class NumberToRMB {

private final String\[\] hanArr = \{"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"\};  
private final String\[\] unitArr = \{"仟", "", "十", "佰"\};  
private final String\[\] tag = \{"元", "万", "亿"\};  
public String toHanStr(double num) \{  
    String result = "";  
    long zheng = (long)num;  
    //long xiao = Math.round((num - zheng) \* 100);//如果需要四舍五入，就用这个方法，但是小数点后  
                                                  //两位依次为99时，第三位不能>=5,否则会报错  
    long xiao = (long)((num - zheng) \* 100);//如果不需要四舍五入，就用这个方法  
    /\*整数部分为0单独考虑\*/  
    if(0 == zheng) \{  
        int tempJiao = (int)(xiao / 10);  
        int tempFen = (int)(xiao % 10);  
        if(tempJiao != 0) \{  
            result += hanArr\[tempJiao\] + "角";  
        \}  
        if(tempFen != 0) \{  
            result += hanArr\[tempFen\] + "分";  
        \}  
        return result;  
    \}  
    String zhengStr = String.valueOf(zheng);  
    int len = zhengStr.length();  
    int tempLen = 0;  
    /\*处理整数部分\*/  
    for(int i = 0; i < len; i++) \{  
        int temp = zhengStr.charAt(i) - 48;  
        int part = (len - i - 1) / 4; //当前字符处于哪个段  
        int location = (len - i - 1) % 4; //当前字符处于该段的具体哪个位置  
        if(location != 0) \{ //不是该段的最后一个  
            if(temp != 0) \{ //当前字符不为0  
                result += hanArr\[temp\] + unitArr\[(len - i) % 4\]; continue;  
            \} else \{ //当前字符为0  
                tempLen = result.length();  
                if(3 == location && result.charAt(tempLen - 1) != '零') \{ //当前字符为0且为该段第一个  
                    result += "零"; continue;  
                \} else \{  
                    tempLen = result.length();  
                    if(result.charAt(tempLen - 1) == '零') \{  
                        continue;  
                    \} else \{  
                        result += "零"; continue;  
                    \}  
                \}  
            \}  
        \} else \{ //是该段最后一个  
            if(temp != 0) \{  
                result += hanArr\[temp\] + tag\[part\]; continue;  
            \} else \{  
                tempLen = result.length();  
                if(result.charAt(tempLen - 1) != '零') \{  
                    result += tag\[part\]; continue;  
                \} else \{  
                    if(result.charAt(tempLen - 2) == '亿' || result.charAt(tempLen - 2) == '万') \{  
                        continue;  
                    \} else \{  
                        result = result.substring(0, tempLen - 1) + tag\[part\]; continue;  
                    \}  
                \}  
            \}  
        \}  
    \}  
    /\*处理小数部分\*/  
    int jiao = (int)(xiao / 10);  
    int fen = (int)(xiao % 10);  
    if(jiao != 0) \{  
        result += hanArr\[jiao\] + "角";  
    \}  
    if(fen != 0) \{  
        result += hanArr\[fen\] + "分";  
    \}  
    /\*排除输入形式如60 0000 0000.00，输出为“陆十亿零”的情况\*/  
    tempLen = result.length();  
    if(result.charAt(tempLen - 1) == '零') \{  
        result = result.substring(0, tempLen - 1);  
    \}  
    tempLen = result.length();  
    if(result.charAt(tempLen - 1) == '元') \{  
        result += "整";  
    \}  
    if(result.charAt(tempLen - 1) == '万' || result.charAt(tempLen - 1) == '亿') \{  
        result += "元整";  
    \}  
    return result;  
\}  
public static void main(String\[\] args) \{  
NumberToRMB ntr = new NumberToRMB();  
    System.out.println(ntr.toHanStr(6000000000.0000));  
    System.out.println(ntr.toHanStr(600100.000));  
    System.out.println(ntr.toHanStr(1006.333));  
    System.out.println(ntr.toHanStr(10.111));  
\}

}

部分算法如下：

   int len = zhengStr.length();//取整数部分字符串长度
   for(i = 0; i < len; i++)//遍历整个整数字符串
       int temp = zhengStr.charAt(i) - 48;//当前字符转为数值
       int part = (len - i - 1) / 4;//当前字符位于那一段
       int location = (len - i - 1) % 4;//当前字符处于段的那一个位置
       if 当前字符不是本段最后一个
           if 当前字符不为‘0’    result += 转换成的繁体字 + 单位;    continue;
           else 当前字符为‘0’
               if 当前字符是该段第一个字符并且result串的最后一个字符!='零' result += '零';continue;
               else
                   if result串的最后一个字符为'零'    continue;
                   else result串的最后一个字符不为'零'    result += '零';
       else 当前字符是本段最后一个
           if 当前字符不为‘0’    result += 转换成的繁体字 + 段单位;    continue;
           else 当前字符为'0'
               if result串的最后一个字符 != '零'    result += 段单位;    continue;
               else resutl串的最后一个字符 == '零'
                   if result串的倒数第二个字符为'亿'或者‘万’    continue;
                   else result串的倒数第二个字符不为'亿'或者'万'  result+=result串去零+段单位;continue;